第十次作业

 1.输入6位密码,再次输入密码,如果不够6位,提示,位数不对,如果两次不一致,提示两次密码不一致。
package sykjxy.com;
import java.util.Scanner;
public class shuiguo {

public static void pw()
{
Scanner input=new Scanner(System.in);
String pass;
String repass;
System.out.println("请输入6位密码");
pass=input.next();
testfun_1(pass);
System.out.println("请重新输入密码");
repass=input.next();
testfun_1(repass);
testfun_2(pass,repass);
}
public static void testfun_2(String test,String retest)
{
if(!test.equals(retest))
{
System.out.println("密码不一致");
System.exit(0);
}
}
public static void testfun_1(String test)
{
if(test.length()!=6)
{
System.out.println("位数不对");
System.exit(0);
}
}


public static void main(String[] args) {
// TODO Auto-generated method stub
pw();
}

}
2.输入一个字符串,判断里面数字、大写字母、小写字母,其他字符的个数
package sykjxy.com;
import java.util.Scanner;
public class shuiguo {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input=new Scanner(System.in);
int a=0;
int s=0;
int b=0;
int f=0;
System.out.println("请输入字符串");
String test=input.next();

for(char i:test.toCharArray())
{
if(i<=57&&i>=48)
{
a++;
}else if(i<=90&&i>=65)
{
s++;
}else if(i<=122&i>=97)
{
b++;
}else
{
f++;
}
}
System.out.println("数字有:"+a+"个");
System.out.println("大写字母有:"+s+"个");
System.out.println("小写字母有:"+b+"个");
System.out.println("其他字符有:"+f+"个");

}

}

 

5、利用接口实现动态的创建对象[选做题]

• 5.1 创建4个类:苹果、香蕉、葡萄、园丁  

• 5.2 在三种水果的构造方法中打印一句话.以苹果类为例

package sykj.com;

public class apple implements fruit {

public apple() {

System.out.println("苹果类");

}

}

package sykj.com;

public class banana implements fruit {



public banana() {

System.out.println("香蕉类");

}

}

package sykj.com;

public interface fruit {
}

package sykj.com;

public class grape implements fruit {

public grape() {

System.out.println("葡萄类");

}
}

package sykj.com;

import java.util.Scanner;

public class lei {

public fruit create() {

Scanner input = new Scanner(System.in);

System.out.println("请输入");

String name = input.next();

fruit b = null;

if (name.equals("苹果")) {

b = new apple();

} else if (name.equals("香蕉")) {

b = new banana();

} else if (name.equals("葡萄")) {

b = new grape();

}

return b;


}

public static void main(String[] args) {

lei x = new lei();

x.create();


}
}

 

posted @ 2023-06-26 18:42  小楠参  阅读(29)  评论(0)    收藏  举报