任务四
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#include<stdio.h> #define N 10 typedef struct { char isbn[20]; char name[80]; char author[80]; double sales_price; int sales_count; }Book; void output(Book x[],int n); void sort(Book x[],int n); double sales_amount(Book x[],int n); int main() { Book x[N]={{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51}, {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30}, {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27}, {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49}, {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42}, {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}, {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42}, {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55}, {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}}; printf("图书销售排名（按销售册数）：\n"); sort(x,N); output(x,N); printf("\n图书销售总额：%.2f\n",sales_amount(x,N)); return 0; } void sort(Book x[],int n) { int i,j; Book t; for(i=0;i<n;i++) { for(j=0;j<n-1-i;j++) { if(x[j].sales_count<x[j+1].sales_count) { t=x[j]; x[j]=x[j+1]; x[j+1]=t; } } } } double sales_amount(Book x[],int n) { double sum=0; int i; for(i=0;i<n;i++) sum+=x[i].sales_price*x[i].sales_count; return sum; } void output(Book x[],int n) { int i; printf("ISBN号 书名 作者 售价 销售册数\n"); for(i=0;i<n;i++) printf("%-20s%-27s%-20s%-20g%-20d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count); }
任务5
#include <stdio.h> typedef struct { int year; int month; int day; } Date; void input(Date *pd); int day_of_year(Date d); int compare_dates(Date d1, Date d2); void test1() { Date d; int i; printf("输入日期:(以形如2025-12-19这样的形式输入)\n"); for(i = 0; i < 3; ++i) { input(&d); printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d)); } } void test2() { Date Alice_birth, Bob_birth; int i; int ans; printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n"); for(i = 0; i < 3; ++i) { input(&Alice_birth); input(&Bob_birth); ans = compare_dates(Alice_birth, Bob_birth); if(ans == 0) printf("Alice和Bob一样大\n\n"); else if(ans == -1) printf("Alice比Bob大\n\n"); else printf("Alice比Bob小\n\n"); } } int main() { printf("测试1: 输入日期, 打印输出这是一年中第多少天\n"); test1(); printf("\n测试2: 两个人年龄大小关系\n"); test2(); } void input(Date *pd) { scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day); } int day_of_year(Date d) { int days; switch(d.month) { case 1:days=d.day;break; case 2:days=31+d.day;break; case 3:days=59+d.day;break; case 4:days=90+d.day;break; case 5:days=120+d.day;break; case 6:days=151+d.day;break; case 7:days=181+d.day;break; case 8:days=212+d.day;break; case 9:days=243+d.day;break; case 10:days=273+d.day;break; case 11:days=304+d.day;break; case 12:days=334+d.day;break; default:break; } if(d.year%4==0&&d.year%100!=0||d.year%400==0) if(d.month>2) days+=1; return days; } int compare_dates(Date d1, Date d2) { if(d1.year>d2.year) return 1; else if(d1.year<d2.year) return -1; else { if(d1.month>d2.month) return 1; else if(d1.month<d2.month) return -1; else { if(d1.day>d2.day) return 1; else if(d1.day<d2.day) return -1; else return 0; } } }
任务6
#include <stdio.h> #include <string.h> enum Role {admin, student, teacher}; typedef struct { char username[20]; char password[20]; enum Role type; } Account; void output(Account x[], int n); int main() { Account x[] = {{"A1001", "123456", student}, {"A1002", "123abcdef", student}, {"A1009", "xyz12121", student}, {"X1009", "9213071x", admin}, {"C11553", "129dfg32k", teacher}, {"X3005", "921kfmg917", student}}; int n; n = sizeof(x)/sizeof(Account); output(x, n); return 0; } void output(Account x[], int n) { int i,j; for(i=0;i<n;i++) { for(j=0;j<strlen(x[i].password);j++) x[i].password[j]='*'; printf("%-10s%-16s",x[i].username,x[i].password); switch(x[i].type) { case 0:{printf("admin\n");break;} case 1:{printf("student\n");break;} case 2:{printf("teacher\n");break;}<br> default:break; } } }
任务7
#include <stdio.h> #include <string.h> #define N 10 typedef struct { char name[20]; char phone[12]; int vip; } Contact; void set_vip_contact(Contact x[], int n, char name[]); void output(Contact x[], int n); void display(Contact x[], int n); int main() { Contact list[N] = {{"刘一", "15510846604", 0}, {"陈二", "18038747351", 0}, {"张三", "18853253914", 0}, {"李四", "13230584477", 0}, {"王五", "15547571923", 0}, {"赵六", "18856659351", 0}, {"周七", "17705843215", 0}, {"孙八", "15552933732", 0}, {"吴九", "18077702405", 0}, {"郑十", "18820725036", 0}}; int vip_cnt, i; char name[20]; printf("显示原始通讯录信息: \n"); output(list, N); printf("\n输入要设置的紧急联系人个数: "); scanf("%d", &vip_cnt); printf("输入%d个紧急联系人姓名:\n", vip_cnt); for(i = 0; i < vip_cnt; ++i) { scanf("%s", name); set_vip_contact(list, N, name); } printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n"); display(list, N); return 0; } void set_vip_contact(Contact x[], int n, char name[]) { int i; for(i=0;i<n;i++) { if(strcmp(x[i].name,name)==0) x[i].vip=1; } } void display(Contact x[], int n) { int i,j; Contact t; for(i=0;i<n;i++) for(j=i+1;j<n;j++) if(strcmp(x[i].name,x[j].name)>0) { t=x[i]; x[i]=x[j]; x[j]=t; } for(i=0;i<n;i++) { if(x[i].vip==1) { printf("%-10s%-15s", x[i].name, x[i].phone); printf("*\n"); } } for(i=0;i<n;i++) { if(x[i].vip==0) printf("%-10s%-15s\n", x[i].name, x[i].phone); } } void output(Contact x[], int n) { int i; for(i = 0; i < n; ++i) { printf("%-10s%-15s", x[i].name, x[i].phone); if(x[i].vip) printf("%5s", "*"); printf("\n"); } }
