strlen 老瓶装新酒

前言 - strlen 概述

　　无意间扫到 glibc strlen.c 中代码, 久久不能忘怀. 在一无所知的编程生涯中又记起点点滴滴:

编程可不是儿戏 ❀, 有些难, 也有些不舍. 而 strlen 仿佛还在那个求学的年代, 还是那么青涩诱人 ~

/* Copyright (C) 1991-2020 Free Software Foundation, Inc.
   This file is part of the GNU C Library.
   Written by Torbjorn Granlund (tege@sics.se),
   with help from Dan Sahlin (dan@sics.se);
   commentary by Jim Blandy (jimb@ai.mit.edu).

   The GNU C Library is free software; you can redistribute it and/or
   modify it under the terms of the GNU Lesser General Public
   License as published by the Free Software Foundation; either
   version 2.1 of the License, or (at your option) any later version.

   The GNU C Library is distributed in the hope that it will be useful,
   but WITHOUT ANY WARRANTY; without even the implied warranty of
   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
   Lesser General Public License for more details.

   You should have received a copy of the GNU Lesser General Public
   License along with the GNU C Library; if not, see
   <https://www.gnu.org/licenses/>.  */

#include <string.h>
#include <stdlib.h>

#undef strlen

#ifndef STRLEN
# define STRLEN strlen
#endif

/* Return the length of the null-terminated string STR.  Scan for
   the null terminator quickly by testing four bytes at a time.  */
size_t
STRLEN (const char *str)
{
  const char *char_ptr;
  const unsigned long int *longword_ptr;
  unsigned long int longword, himagic, lomagic;

  /* Handle the first few characters by reading one character at a time.
     Do this until CHAR_PTR is aligned on a longword boundary.  */
  for (char_ptr = str; ((unsigned long int) char_ptr
            & (sizeof (longword) - 1)) != 0;
       ++char_ptr)
    if (*char_ptr == '\0')
      return char_ptr - str;

  /* All these elucidatory comments refer to 4-byte longwords,
     but the theory applies equally well to 8-byte longwords.  */

  longword_ptr = (unsigned long int *) char_ptr;

  /* Bits 31, 24, 16, and 8 of this number are zero.  Call these bits
     the "holes."  Note that there is a hole just to the left of
     each byte, with an extra at the end:

     bits:  01111110 11111110 11111110 11111111
     bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD

     The 1-bits make sure that carries propagate to the next 0-bit.
     The 0-bits provide holes for carries to fall into.  */
  himagic = 0x80808080L;
  lomagic = 0x01010101L;
  if (sizeof (longword) > 4)
    {
      /* 64-bit version of the magic.  */
      /* Do the shift in two steps to avoid a warning if long has 32 bits.  */
      himagic = ((himagic << 16) << 16) | himagic;
      lomagic = ((lomagic << 16) << 16) | lomagic;
    }
  if (sizeof (longword) > 8)
    abort ();

  /* Instead of the traditional loop which tests each character,
     we will test a longword at a time.  The tricky part is testing
     if *any of the four* bytes in the longword in question are zero.  */
  for (;;)
    {
      longword = *longword_ptr++;

      if (((longword - lomagic) & ~longword & himagic) != 0)
    {
      /* Which of the bytes was the zero?  If none of them were, it was
         a misfire; continue the search.  */

      const char *cp = (const char *) (longword_ptr - 1);

      if (cp[0] == 0)
        return cp - str;
      
      if (cp[1] == 0)
        return cp - str + 1;
      if (cp[2] == 0)
        return cp - str + 2;
      if (cp[3] == 0)
        return cp - str + 3;
      if (sizeof (longword) > 4)
        {
          if (cp[4] == 0)
        return cp - str + 4;
          if (cp[5] == 0)
        return cp - str + 5;
          if (cp[6] == 0)
        return cp - str + 6;
          if (cp[7] == 0)
        return cp - str + 7;
        }
    }
    }
}
libc_hidden_builtin_def (strlen)

正文 - 思考和分析

1. unsigned long int 字节多大 4 字节, 8 字节 ?

  unsigned long int longword, himagic, lomagic;

long 具体多长和平台有关, 例如大多数 linux , x86 sizeof (long) = 4, x64 sizeof (long) = 8.

window x86, x64 sizeof (long) = 4. (2020年05月28日), C 标准保证 sizeof(long) >= sizeof (int)

具体多少字节交给了实现方.

2. ((unsigned long int) char_ptr & (sizeof (longword) - 1)) 位对齐 ?

  /* Handle the first few characters by reading one character at a time.
     Do this until CHAR_PTR is aligned on a longword boundary.  */
  for (char_ptr = str; ((unsigned long int) char_ptr
            & (sizeof (longword) - 1)) != 0;
       ++char_ptr)
    if (*char_ptr == '\0')
      return char_ptr - str;

起始的这些代码的作用是, 让 chart_ptr 按照 sizeof (unsigned long) 字节大小进行位对齐.

这涉及到多数计算机硬件对齐有要求和性能方面的考虑等等(性能是主要因素).

3. himagic = 0x80808080L; lomagic = 0x01010101L; what fuck ?

  /* Bits 31, 24, 16, and 8 of this number are zero.  Call these bits
     the "holes."  Note that there is a hole just to the left of
     each byte, with an extra at the end:

     bits:  01111110 11111110 11111110 11111111
     bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD

     The 1-bits make sure that carries propagate to the next 0-bit.
     The 0-bits provide holes for carries to fall into.  */
  himagic = 0x80808080L;
  lomagic = 0x01010101L;
  if (sizeof (longword) > 4)
    {
      /* 64-bit version of the magic.  */
      /* Do the shift in two steps to avoid a warning if long has 32 bits.  */
      himagic = ((himagic << 16) << 16) | himagic;
      lomagic = ((lomagic << 16) << 16) | lomagic;
    }
  if (sizeof (longword) > 8)
    abort ();

  /* Instead of the traditional loop which tests each character,
     we will test a longword at a time.  The tricky part is testing
     if *any of the four* bytes in the longword in question are zero.  */
  for (;;)
    {
      longword = *longword_ptr++;

      if (((longword - lomagic) & ~longword & himagic) != 0)
    {

3.1 (((longword - lomagic) & ~longword & himagic) != 0) ? mmp ?

可能这就是艺术吧. 想到这个想法的, 真是个天才啊! 好巧妙. 哈哈哈. 我们会分两个小点说明下.

首次看, 感觉有点萌. 我这里用个简单的思路来带大家理解这个问题. 上面代码主要围绕

sizeof (unsigned long) 4 字节和 8 字节去处理得到. 我们简单点, 通过处理 1 字节, 类比递归机制.

搞懂这个公式背后的原理 (ˇˍˇ) ～

/**
 * himagic      : 1000 0000
 * lomagic      : 0000 0001
 * longword     : XXXX XXXX
 * /
unsigned long himagic = 0x80L;
unsigned long lomagic = 0x01L;

unsigned long longword ;

随后我们仔细分析下面公式

((longword - lomagic) & ~longword & himagic)

( & himagic ) = ( & 1000 0000) 表明最终只在乎最高位.

longword 分三种情况讨论

longword     : 1XXX XXXX  128 =< x <= 255
longword     : 0XXX XXXX  0 < x < 128
longword     : 0000 0000  x = 0

第一种 longword = 1XXX XXXX

那么 ~longword = 0YYY YYYY 显然 ~ longword & himagic = 0000 0000 不用继续了.

第二种 longword = 0XXX XXXX 且不为 0, 及不小于 1

显然 (longword - lomagic) = 0ZZZ ZZZ >= 0 且 < 127, 因为 lomagic = 1;

此刻 (longword - lomagic) & himagic = 0ZZZ ZZZZ & 1000 0000 = 0 , 所以也不需要继续了.

第三种 longword = 0000 0000

那么 ~longword & himagic = 1111 1111 & 1000 0000 = 1000 000;

再看 (longword - lomagic) = (0000 0000 - 0000 0001) , 由于无符号数减法是按照

(补码(0000 0000) + 补码(-000 0001)) = (补码(0000 0000) + 补码(~000 0001 + 1))

= (补码(0000 0000) + 补码(1111 1111)) = 1111 1111 (快捷的可以查公式得到最终结果),

因而此刻最终结果为 1111 1111 & 1000 0000 = 1000 0000 > 0.

综合讨论, 可以根据上面公式巧妙的筛选出值是否为 0. 对于 2字节, 4 字节, 8 字节, 思路完全相似.

3.2 (sizeof (longword) > 4) ? (sizeof (longword) > 8) 为什么不用宏, 大展宏图呗 ?

宏可以做到多平台源码共享, 无法做到多平台二进制共享. glibc 这么通用项目, 可移植性影响因子

可能会很重. (性能是毒酒, 想活的久还是少喝 ~ )

4. libc_hidden_builtin_def (strlen) ? 闹哪样 ~

理解这个东西, 要引入些场外信息 (不同编译参数会不一样, 这里只抽取其中一条分支解法)

// file : glibc-2.31/include/libc-symbols.h

libc_hidden_builtin_def (strlen)

#define libc_hidden_builtin_def(name) libc_hidden_def (name)

# define libc_hidden_def(name) hidden_def (name)

/* Define ALIASNAME as a strong alias for NAME.  */
# define strong_alias(name, aliasname) _strong_alias(name, aliasname)
# define _strong_alias(name, aliasname) \
  extern __typeof (name) aliasname __attribute__ ((alias (#name))) \
    __attribute_copy__ (name);

/* For assembly, we need to do the opposite of what we do in C:
   in assembly gcc __REDIRECT stuff is not in place, so functions
   are defined by its normal name and we need to create the
   __GI_* alias to it, in C __REDIRECT causes the function definition
   to use __GI_* name and we need to add alias to the real name.
   There is no reason to use hidden_weak over hidden_def in assembly,
   but we provide it for consistency with the C usage.
   hidden_proto doesn't make sense for assembly but the equivalent
   is to call via the HIDDEN_JUMPTARGET macro instead of JUMPTARGET.  */
#  define hidden_def(name)    strong_alias (name, __GI_##name)

/* Undefine (also defined in libc-symbols.h).  */
#undef __attribute_copy__
#if __GNUC_PREREQ (9, 0)
/* Copies attributes from the declaration or type referenced by
   the argument.  */
# define __attribute_copy__(arg) __attribute__ ((__copy__ (arg)))
#else
# define __attribute_copy__(arg)
#endif

利用上面宏定义, 进行展开

libc_hidden_builtin_def (strlen)
|

hidden_def (strlen)
|

strong_alias (strlen, __GI_strlen)
|

_strong_alias (strlen, __GI_strlen)
|

extern __typeof (strlen) __GI_strlen __attribute__ ((alias ("strlen"))) __attribute_copy__ (strlen);
|

extern __typeof (strlen) __GI_strlen __attribute__ ((alias ("strlen"))) __attribute__ ((__copy__ (strlen)));
``

其中 GUN C 扩展语法

　　__typeof (arg) : 获取变量的声明的类型

　　__attribute__ ((__copy__ (arg))) : GCC 9 以上版本 attribute copy 复制特性

　　alias_name __attribute__ ((alias (name))) : 为 name 声明符号别名 alias name.

总结: libc_hidden_builtin_def (strlen) 意思是基于 strlen 符号, 重新定义一个符号别名 __GI_strlen.

(补充资料 strong_alias 注释)

strlen 工程代码有很多种, 我们这里选择一个通用 glibc 版本去思考和分析. 有兴趣可以自行查阅更多.

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posted on 2020-05-29 21:37 喜欢兰花山丘阅读(593) 评论(1) 编辑收藏举报

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