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获取URL参数

    function queryParam(url = location.href) {
        url = url.substring(url.indexOf('?') + 1)
        const params = {}
        url.split('&').forEach(v => {
          const temp = v.split('=')
          if (temp.length === 2) {
            params[temp[0]] = temp[1]
          }
        })
        return params
      }
posted @ 2020-03-14 14:41  fsdffsdf  阅读(189)  评论(0)    收藏  举报