gson.fromJson 中java 类要求

java类的字段名称必须与json名称一致 

{"ErrorInfo":"某某某","Result":""}

Gson gson = new Gson();
ResultInfo resultInfo = gson.fromJson(txtJsonResult, ResultInfo.class);
java类必须如下
public class ResultInfo {
public String getErrorInfo() {
return ErrorInfo;
}

public void setErrorInfo(String errorInfo) {
this.ErrorInfo = errorInfo;
}

private String ErrorInfo ;

public String getResult() {
return Result;
}

public void setResult(String result) {
this.Result = result;
}

private String Result ;
}

posted on 2016-07-03 13:24  oyl  阅读(334)  评论(0)    收藏  举报

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