Leetcode 239: Sliding Window Maximum

Given an array nums, there is a sliding window of size k which is moving from the very left of the array to the very right. You can only see the k numbers in the window. Each time the sliding window moves right by one position.

For example,
Given nums = [1,3,-1,-3,5,3,6,7], and k = 3.

Window position                Max
---------------               -----
[1  3  -1] -3  5  3  6  7       3
 1 [3  -1  -3] 5  3  6  7       3
 1  3 [-1  -3  5] 3  6  7       5
 1  3  -1 [-3  5  3] 6  7       5
 1  3  -1  -3 [5  3  6] 7       6
 1  3  -1  -3  5 [3  6  7]      7

Therefore, return the max sliding window as [3,3,5,5,6,7].

Note: 
You may assume k is always valid, ie: 1 ≤ k ≤ input array's size for non-empty array.

Follow up:
Could you solve it in linear time?

 

 1 public class Solution {
 2     public int[] MaxSlidingWindow(int[] nums, int k) {
 3         int len = nums.Length;
 4         if (len == 0 || len < k) return new int[0];
 5         
 6         var result = new int[len - k + 1];
 7         var window = new List<int>(k);
 8         
 9         for (int i = 0; i < len; i++)
10         {
11             while (window.Count > 0 && i - window[0] >= k)
12             {
13                 window.RemoveAt(0);
14             }
15             
16             while (window.Count >0 && nums[i] > nums[window[window.Count - 1]])
17             {
18                 window.RemoveAt(window.Count - 1);
19             }
20             
21             window.Add(i);
22             
23             if (i >= k - 1)
24             {
25                 result[i - k + 1] = nums[window[0]];
26             }
27         }
28         
29         return result;
30     }
31 }

 

posted @ 2017-12-05 05:25  逸朵  阅读(153)  评论(0)    收藏  举报