一人为镜可以明得失

摘要： 列表排序 冒泡法lists = [20,40,4,5,6,7,2,32,68,59]lang = len(lists)for i in range(lang): for j in range(i+1,lang): if lists[i]>lists[j]: lists[i],lists[j] = l 阅读全文