面试题58:翻转字符串

# -*- coding:utf-8 -*-
class Solution:
    def ReverseSentence(self, s):
        # write code here
        # 先边界条件
        if not s:
            return s
# 注意:s.split(" ") 这个的必要性 s = list([i for i in s.split(" ")]) res = s[::-1] return " ".join(res)

  采用:reverse()

def ReverseSentence(s):
        word = s.split(' ')
        word.reverse()
        return ' '.join(word)

  

posted @ 2019-08-21 14:38  lililili——  阅读(157)  评论(0)    收藏  举报