package com.lixuan.houhou;
public class SxisuArray {
public static void main(String[] args) {
//稀疏数组 :创建一个二维数组11*11 0:没有棋子 1:黑棋 2:白棋
int[][] array1 = new int[11][11];
array1[1][2] = 1;
array1[2][3] = 2;
//输出原始的数组
System.out.println("输出原始数组");
for (int[] ints : array1) {
for (int anInt : ints) {
System.out.print(anInt + "\t");
}
System.out.println("\n");
}
//转换为稀疏数组保存
//1.获取有效值的个数
int sum = 0;
for (int i = 0; i < array1.length; i++) {
for (int j = 0; j < array1[i].length; j++) {
if (array1[i][j] != 0) {
sum++;
}
}
}
System.out.println("有效值个数为" + sum);
//2.创建一个稀疏数组的数组
int[][] array2 = new int[sum + 1][3];
array2[0][0] = 11;
array2[0][1] = 11;
array2[0][2] = sum;
//遍历上面array二维数组,将非0的值存放稀疏数组中
int count = 0;
for (int i = 0; i < array1.length; i++) {
for (int j = 0; j < array1[i].length; j++) {
if (array1[i][j] != 0) {
count++;
array2[count][0] = i;
array2[count][1] = j;
array2[count][2] = array1[i][j];
}
}
}
//输出稀疏数组
System.out.println("稀疏数组");
for (int i = 0; i < array2.length; i++) {
System.out.println(array2[i][0] + "\t" + array2[i][1] + "\t" + array2[i][2] + "\t");
}
//还原稀疏数组
//读取保存稀疏数组中特殊值
int[][] array3 = new int[array2[0][0]][array2[0][1]];
//给其他非特殊元素还原值
for (int i = 1; i < array2.length; i++) {
array3[array2[i][0]][array2[i][1]] = array2[i][2];
}
//打印还原数组array3
for (int[] ints : array3) {
for (int anInt : ints) {
System.out.print(anInt + "\t");
}
System.out.println("\n");
}
}
}
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