package com.lixuan.houhou;

public class SxisuArray {
public static void main(String[] args) {
//稀疏数组 :创建一个二维数组11*11 0:没有棋子 1:黑棋 2:白棋
int[][] array1 = new int[11][11];
array1[1][2] = 1;
array1[2][3] = 2;
//输出原始的数组
System.out.println("输出原始数组");

    for (int[] ints : array1) {
        for (int anInt : ints) {
            System.out.print(anInt + "\t");
        }
        System.out.println("\n");
    }
    //转换为稀疏数组保存
    //1.获取有效值的个数
    int sum = 0;
    for (int i = 0; i < array1.length; i++) {
        for (int j = 0; j < array1[i].length; j++) {
            if (array1[i][j] != 0) {
                sum++;
            }
        }
    }
    System.out.println("有效值个数为" + sum);
    //2.创建一个稀疏数组的数组
    int[][] array2 = new int[sum + 1][3];

    array2[0][0] = 11;
    array2[0][1] = 11;
    array2[0][2] = sum;

    //遍历上面array二维数组,将非0的值存放稀疏数组中
    int count = 0;
    for (int i = 0; i < array1.length; i++) {
        for (int j = 0; j < array1[i].length; j++) {
            if (array1[i][j] != 0) {
                count++;
                array2[count][0] = i;
                array2[count][1] = j;
                array2[count][2] = array1[i][j];
            }

        }
    }
    //输出稀疏数组
    System.out.println("稀疏数组");
    for (int i = 0; i < array2.length; i++) {
        System.out.println(array2[i][0] + "\t" + array2[i][1] + "\t" + array2[i][2] + "\t");

    }

    //还原稀疏数组
    //读取保存稀疏数组中特殊值
    int[][] array3 = new int[array2[0][0]][array2[0][1]];

    //给其他非特殊元素还原值
    for (int i = 1; i < array2.length; i++) {
        array3[array2[i][0]][array2[i][1]] = array2[i][2];

    }
    //打印还原数组array3
    for (int[] ints : array3) {
        for (int anInt : ints) {
            System.out.print(anInt + "\t");
        }
        System.out.println("\n");
    }


}
}
posted on 2025-09-24 20:40  前向李之一  阅读(6)  评论(0)    收藏  举报