随笔分类 -  UNCTF

UNCTF2019：BABYRSA
摘要：下载附件，解压后有一个加密文件和rsa.py代码如下： flag = open('flag.txt','r').read() N = 221 e = 5 enc = b'' for i in flag: enc += bytes([pow(ord(i),e,N)]) encrypt = open(' 阅读全文
posted @ 2020-12-10 21:45 浩琦很好奇 阅读(164) 评论(0) 推荐(0)