实验四

#include<iostream>
#include<cassert>

using std::cout;
using std::endl;
class vectorInt {
public:
    vectorInt(int n, int m);
    vectorInt(int n);
    vectorInt(const vectorInt& a);
    ~vectorInt();
    friend void output(vectorInt&p1);
    int& at(int index);
private:
    int size;
    int* p;
};
vectorInt::vectorInt(int n) :size(n) {
    cout << "constructor 1 called." << endl;
    p = new int[size];
    int m = 1;
    for (int i = 0; i < size; i++)
    {
        p[i] = m;
    }
};
vectorInt::vectorInt(int n, int m) :size(n) {
    
    p = new int[size];
    for (int i = 0; i < size; i++)
    {
        p[i] = m;
    }
};
vectorInt::vectorInt(const vectorInt& a) :size{ a.size }
{
    cout << "constructor 2 called." << endl;
    cout << "copy constructor called." << endl;
    p = new int[size];
    for (int i = 0; i < size; i++)
    {
        p[i] = a.p[i];
    }
}
vectorInt::~vectorInt()
{
    delete[] p;
}
void output(vectorInt& p1)
{
    int*p = p1.p;
    for (int i = 0; i < p1.size; i++)
    {
        cout << p[i] <<" ";
    }
    cout << endl;
}
inline int& vectorInt::at(int index)
{
    assert(index >= 0 && index < size);
    return p[index];
}

#include <iostream>
#include <cassert>
using namespace std;
class Matrix
{
public:
    Matrix(int n);                     // 构造函数,构造一个n*n的矩阵
    Matrix(int n, int m);              // 构造函数,构造一个n*m的矩阵
    Matrix(const Matrix& X);           // 复制构造函数,使用已有的矩阵X构造
    ~Matrix();                         //析构函数
    void set(const double* pvalue);     // 用pvalue指向的连续内存块数据为矩阵赋值
    void set(int i, int j, int value); //设置矩阵第i行第j列元素值为value
    double& at(int i, int j);          //返回矩阵第i行第j列元素的引用
    double at(int i, int j) const;     // 返回矩阵第i行第j列元素的值
    int get_lines() const;             //返回矩阵行数
    int get_cols() const;              //返回矩列数
    void print() const;                // 按行打印输出矩阵
private:
    int lines; // 矩阵行数
    int cols;  // 矩阵列数
    double* p; // 指向存放矩阵数据的内存块的首地址
};


// 类Matrix的实现:待补足
Matrix::Matrix(int n) :lines{ n }, cols{ n }
{
    p = new double[n * n];
}
inline Matrix::Matrix(int n, int m) : lines(n), cols(m)
{
    p = new double[n * m];
}
inline Matrix::Matrix(const Matrix& X) : lines{ X.lines }, cols{ X.cols }
{
    p = new double[lines * cols];
    for (int i = 1; i <= lines * cols; i++)
        p[i] = X.p[i];
}
inline Matrix::~Matrix()
{
    delete[]p;
}
inline void Matrix::set(const double* pvalue)
{
    for (int i = 0; i < lines * cols; i++)
        p[i] = pvalue[i];
}
inline void Matrix::set(int i, int j, int value)
{
    p[i * cols + j] = value;
}
inline double& Matrix::at(int i, int j)
{
    return p[i * cols + j];
}
inline double Matrix::at(int i, int j) const
{
    return p[i * cols + j];
}
inline int Matrix::get_lines() const
{
    return lines;
}
inline int Matrix::get_cols() const
{
    return cols;
}
inline void Matrix::print() const
{
    for (int i = 0; i < lines; i++)
    {
        for (int j = 0; j < cols; j++)
            cout << p[i * cols + j] << ",";
        cout << endl;
    }

 

posted @ 2022-11-07 21:47  刘海烽  阅读(23)  评论(0)    收藏  举报