摘要:
最笨的办法当然是二层嵌套循环,但觉得应该有更好的方法,但是着实想不出来,想听听大家的意见,大家帮帮小弟 i.e string[] A={"X","Y","Z","W"}; string[] B={"X","E","Z","U","V"}; 只要发现B中有一个A的元素就可以 阅读全文
posted @ 2007-11-03 15:29
lexus
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摘要:
最笨的办法当然是二层嵌套循环,但觉得应该有更好的方法,但是着实想不出来,想听听大家的意见,大家帮帮小弟 i.e string[] A={"X","Y","Z","W"}; string[] B={"X","E","Z","U","V"}; 只要发现B中有一个A的元素就可以 阅读全文
posted @ 2007-11-03 15:29
lexus
阅读(594)
评论(4)
推荐(0)
|