python socket: sending and receiving 16 bytes - Stack Overflow
python socket: sending and receiving 16 bytes
up vote 3 down vote favorite
3
See edits below.
I have two programs that communicate through sockets. I'm trying to send a block of data from one to the other. This has been working with some test data, but is failing with others.
s.sendall('%16d' % len(data))
s.sendall(data)
print(len(data))
sends to
size = int(s.recv(16))
recvd = ''
while size > len(recvd):
data = s.recv(1024)
if not data:
break
recvd += data
print(size, len(recvd))
At one end:
s = socket.socket()
s.connect((server_ip, port))
and the other:
c = socket.socket()
c.bind(('', port))
c.listen(1)
s,a = c.accept()
In my latest test, I sent a 7973903 byte block and the receiver reports size as 7973930.
Why is the data block received off by 27 bytes?
Any other issues?
Python 2.7 or 2.5.4 if that matters.
EDIT: Aha - I'm probably reading past the end of the send buffer. If remaining bytes is less than 1024, I should only read the number of remaining bytes. Is there a standard technique for this sort of data transfer? I have the feeling I'm reinventing the wheel.
EDIT2: I'm screwing up by reading the next file in the series. I'm sending file1 and the last block is 997 bytes. Then I send file2, so the recv(1024) at the end of file1 reads the first 27 bytes of file2.
I'll start another question on how to do this better.
Thanks everyone. Asking and reading comments helped me focus.
