上楼梯(凯撒)

题目：

ej^cv`]^/*(*Y(VUR "PJJIGW

思路：

比较flag和ej^c的差的规律

exp:

s = 'ej^cv`]^/*(*Y(VUR "PJJIGW'
ss = "flag"
sss = ""
for i in range(4):
    print(ord(ss[i]) - ord(s[i]))
for i in range(0, len(s)):
    sss += chr(ord(s[i]) + i + 1)
print(sss)

posted @ 2025-05-18 13:38  lethe311  阅读(16)  评论(0)    收藏  举报