牛客网 漂亮的树
https://ac.nowcoder.com/acm/contest/5902/C
感谢LDK大神提供的最后解法
一个点z 到另一个点集合S的最长路为 ans
集合S中的最远点对x,y
ans = max(ans,dis(x,z),dis(y,z));
就是这样了
#include<cstring>
#include<cstdio>
#include<iostream>
#include<algorithm>
#include<vector>
#include<unordered_map>
using namespace std;
typedef long long ll;
const int maxn = 2e5 + 7;
vector<int>G[maxn], ins[maxn];
unordered_map<int, int >id;
int n;
void add(int x, int y) {
G[x].push_back(y);
}
int dep[maxn], top[maxn], fa[maxn], siz[maxn];
int cns[maxn];
int son[maxn];
int dfs1(int x, int f, int d) {
dep[x] = d;
fa[x] = f;
siz[x] = 1;
int s = 0;
for (int i = 0; i < G[x].size(); i++) {
int p = G[x][i];
if (p == f) continue;
dfs1(p, x, d + 1);
siz[x] += siz[p];
if (s < siz[p]) {
s = siz[p];
son[x] = p;
}
}
return 0;
}//haah
int cnt = 0;
int dfs2(int x, int t) {
top[x] = t;
if (!son[x]) return 0;
dfs2(son[x], t);//重儿子重复利用t
for (int i = 0; i < G[x].size(); i++) {
int p = G[x][i];
if (p == fa[x] || p == son[x]) continue;
dfs2(p, p);//轻儿子新建t
}
return 0;
}
int LCA(int u, int v)
{
while (top[u] != top[v])//u、v不在同一条重链上时
{
if (dep[top[u]] > dep[top[v]])//将深度大的上提
u = fa[top[u]];
else
v = fa[top[v]];
}
if (dep[u] < dep[v])//返回u、v中在较上方的那个
return u;
return v;
}
int get(int x, int y) {//点之间的距离
int root = LCA(x, y);
return dep[x] + dep[y] - 2 * dep[root];
}
int main() {
//******准备*********//
int q;
scanf("%d %d", &n, &q);
int x;
int c = 0;
for (int i = 1; i <= n ; i++) {
scanf("%d", &x);
cns[i] = x;
if (id[x] == 0) id[x] = ++c;
ins[id[x]].push_back(i);
}
for (int i = 1; i < n; i++) {
int x, y;
scanf("%d%d", &x, &y);
add(x, y);
add(y, x);
}
dfs1(1, -1, 0);
dfs2(1, 1);
//******开始********//
for (int i = 1; i <= n; i++) {
if (ins[i].size() < 2) continue;
int s = ins[i][0];
int t = ins[i][1];
int ln = get(s, t);
for (int j = 2; j < ins[i].size(); j++) {
int x = ins[i][j];
int a = get(x, s);
int b = get(x, t);
if (a > b) {
if (a > ln) {
ln = a;
t = x;
}
}
else {
if (b > ln) {
ln = b;
s = x;
}
}
}
ins[i].clear();
ins[i].push_back(s);
ins[i].push_back(t);
}
while (q--) {
int x, y;
int ans = 0;
scanf("%d%d", &x, &y);
x = id[x];
y = id[y];
if (ins[x].size() == 0 || ins[y].size() == 0) {
printf("0\n");
}
else {
for (int i = 0; i < ins[x].size(); i++) {
for (int j = 0; j < ins[y].size(); j++) {
int s = ins[x][i];
int t = ins[y][j];
ans = max(get(s, t), ans);
}
}
printf("%d\n", ans);
}
}
return 0;
}
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