算法1-6 计算1~n与1~m每一项相互乘积的和

点击查看代码

#include<stdio.h>
int main(int argc,const char *argv[]){
    int m,n;
    int sum = 0;
    scanf("%d %d",&m,&n);
    for(int i = 1;i <= m;i++){
        for(int j = 1;j <= n;j++){
            sum += i*j; 
        }
    }
    printf("%d",sum);
    return 0;
}