python基于标准库的多线程操作

from concurrent.futures import ThreadPoolExecutor  
from time import sleep  
import concurrent

def worker(num):  
    print(f"Working on {num}")  
    sleep(1)  # 模拟耗时操作  
    print(f"Finished {num}")  
  
def main():  
    with ThreadPoolExecutor(max_workers=5) as executor:  # 创建一个有5个线程的线程池  
        futures = [executor.submit(worker, i) for i in range(10)]  # 提交任务给线程池  
        for future in concurrent.futures.as_completed(futures):  # 等待所有任务完成  
            result = future.result()  # 尽管worker函数没有返回值，但这里可以捕获异常  
  
if __name__ == "__main__":  
    main()