Spring Data JPA的方法命名规则-笔记

关键词	SQL符号	样例	对应JPQL 语句片段
And	and	findByLastnameAndFirstname	… where x.lastname = ?1 and x.firstname = ?2
Or	or	findByLastnameOrFirstname	… where x.lastname = ?1 or x.firstname = ?2
Is,Equals	=	findByFirstname,findByFirstnameIs,findByFirstnameEquals	… where x.firstname = ?1
Between	between xxx and xxx	findByStartDateBetween	… where x.startDate between ?1 and ?2
LessThan	<	findByAgeLessThan	… where x.age < ?1
LessThanEqual	<=	findByAgeLessThanEqual	… where x.age <= ?1
GreaterThan	>	findByAgeGreaterThan	… where x.age > ?1
GreaterThanEqual	>=	findByAgeGreaterThanEqual	… where x.age >= ?1
After	>	findByStartDateAfter	… where x.startDate > ?1
Before	<	findByStartDateBefore	… where x.startDate < ?1
IsNull	is null	findByAgeIsNull	… where x.age is null
IsNotNull,NotNull	is not null	findByAge(Is)NotNull	… where x.age not null
Like	like	findByFirstnameLike	… where x.firstname like ?1
NotLike	not like	findByFirstnameNotLike	… where x.firstname not like ?1
StartingWith	like 'xxx%'	findByFirstnameStartingWith	… where x.firstname like ?1(parameter bound with appended %)
EndingWith	like 'xxx%'	findByFirstnameEndingWith	… where x.firstname like ?1(parameter bound with prepended %)
Containing	like '%xxx%'	findByFirstnameContaining	… where x.firstname like ?1(parameter bound wrapped in %)
OrderBy	order by	findByAgeOrderByLastnameDesc	… where x.age = ?1 order by x.lastname desc
Not	<>	findByLastnameNot	… where x.lastname <> ?1
In	in()	findByAgeIn(Collection ages)	… where x.age in ?1
NotIn	not in()	findByAgeNotIn(Collection ages)	… where x.age not in ?1
TRUE	=true	findByActiveTrue()	… where x.active = true
FALSE	=false	findByActiveFalse()	… where x.active = false
IgnoreCase	upper(xxx)=upper(yyyy)	findByFirstnameIgnoreCase	… where UPPER(x.firstame) = UPPER(?1)