实验7 文件
试验任务3
1.屏幕上正确输出了按分数由高到低的排序的信息,在当前路径下,生成了文本文件file3.dat
2.file3.dat中的信息正确,并且只直观可读
实验任务4
1.正确分数由高到低排序,生成file4.dat,数据信息不直观可读
2
// 从文本数据文件file1.dat中读入数据,按成绩从高到低排序,并将排序结果输出到屏幕上,同时,也以二进制方式存入文件file4.dat中。
#include <stdio.h>
#include <stdlib.h>
#define N 10
// 定义一个结构体类型STU
typedef struct student {
int num;
char name[20];
int score;
}STU;
int main() {
FILE *f;
STU st[N];
int i;
f=fopen("file4.dat","rb");
if(!f){
printf("fail to open file4.dat\n");
exit(0);
}
for(i=0;i<N;i++)
fread(&st[i].num,sizeof(st[i]),1,f);
for(i=0;i<N;i++)
printf("%-6d%-10s%3d\n",st[i].num,st[i].name,st[i].score);
fclose(f);
return 0;
}

试验任务5
#include <stdio.h>
#include <string.h>
const int N = 10;
typedef struct student {
long int id;
char name[20];
float objective;
float subjective;
float sum;
char level[10];
}STU;
void input(STU s[], int n);
void output(STU s[], int n);
void process(STU s[], int n);
int main() {
STU stu[N];
printf("录入%d个考生信息: 准考证号,姓名,客观题得分(<=40),操作题得分(<=60)\n", N);
input(stu, N);
printf("\n对考生信息进行处理: 计算总分,确定等级\n");
process(stu, N);
printf("\n打印考生完整信息: 准考证号,姓名,客观题得分,操作题得分,总分,等级\n");
output(stu, N);
return 0;
}
void input(STU s[], int n) {
FILE*fin;
int i;
fin=fopen("examinee.txt","r") ;
if( !fin ) {
printf("fail to open examinee.txt\n");
}
for(i=0; i<=N; i++) {
fscanf(fin,"%d%s%f%f",&s[i].id,&s[i].name,&s[i].objective,&s[i].subjective);
}
fclose(fin);
}
void output(STU s[], int n) {
FILE*fout;
int i;
for(i=0; i<N; i++) {
printf("%ld %s %12.1f %12.1f %12.1f %8s\n", s[i].id, s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level);
}
fout=fopen("result.txt","w") ;
if( !fout ) {
printf("fail to open result.txt\n");
}
for(i=0; i<N; i++) {
fprintf(fout,"%ld %12.2s %12.1f %12.1f %12.1f %8s\n", s[i].id, s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level);
}
fclose(fout);
}
void process(STU s[], int n) {
int i,j;
STU temp;
for(i=0;i<n;i++)
s[i].sum=s[i].objective+s[i].subjective;
for(j=0;j<n-1;j++){
for(i=0;i<n-1-j;i++){
if(s[i].sum<s[i+1].sum){
temp=s[i+1];
s[i+1]=s[i];
s[i]=temp;
}
}
}
for(i=0;i<n;i++){
if(s[i].sum>=s[n/10].sum)
strcpy(s[i].level,"优秀");
if(s[i].sum>=s[n/2].sum&&s[i].sum<s[n/10].sum)
strcpy(s[i].level,"合格");
if(s[i].sum<s[n/2].sum)
strcpy(s[i].level,"不合格");
}
}


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