前面的题目废话好多啊  ヾ(❀●◡●)ノ滴~儿童卡

每次的羊数都满足关系: an = 2 * (a(n-1) - 1)

#include<stdio.h> int main() { int score[31]; int m , n; score[1] = 4; for(int i=2; i<31; i++) score[i] = (score[i-1] - 1) * 2; scanf("%d" , &n); for(int i=0; i<n; i++) { scanf("%d" , &m); printf("%d\n" , score[m]); } return 0; }
posted on 2017-12-31 20:33  23~  阅读(203)  评论(0)    收藏  举报