python challenge 3 

1 import re
2 fo = open("4","r+")
3 strs = fo.read()
4 #print strs
5 s = ''
6 for res in re.findall(r'[a-z][A-Z]{3}([a-z])[A-Z]{3}[a-z]',strs):
7      s += res
8 print s 
9 #xXXXxXXXx
posted @ 2012-02-10 18:20  lcyang  阅读(163)  评论(0)    收藏  举报