闰年个数(非循环)
#include <stdio.h>
int main()
{
	int n, i, count = 0, test;
	scanf("%d", &n);
	for (i = 1; i <= n; ++i)// 循环版 
	{
		if (i % 4 == 0 && i % 100 != 0 || i % 400 == 0)
		{
			++count;
		}
	}
	// 非循环 
	test = n / 4 - n / 100 + n / 400;// 直接算闰年个数,不用循环 
	printf("test: %d\ncount: %d", test, count);
	return 0;
}========================================Talk is cheap, show me the code=======================================
    CSDN博客地址:https://blog.csdn.net/qq_34115899
 
                    
                     
                    
                 
                    
                 
                
            
         
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浙公网安备 33010602011771号