函数递归 案例一 分形树

# 绘制分形树
import turtle


def draw_brach(brach_length):

if brach_length > 5:
# 绘制右侧树枝
turtle.pencolor("brown")
turtle.pensize(3)
turtle.forward(brach_length)
turtle.right(30)
draw_brach(brach_length - 15)

turtle.left(60)
draw_brach(brach_length - 15)
# 绘制左侧树枝
turtle.right(30)
turtle.up()
turtle.backward(brach_length)
turtle.down()

if brach_length<=10:
turtle.pencolor("green")
turtle.pensize(5)
turtle.forward(brach_length)
turtle.right(30)
draw_brach(brach_length - 15)

turtle.left(60)
draw_brach(brach_length - 15)

turtle.right(30)
turtle.up()
turtle.backward(brach_length)
turtle.down()


def main():
turtle.speed(100)
turtle.left(90)
turtle.up()
turtle.backward(200)
turtle.down()
turtle.pensize(10)
draw_brach(100)

turtle.exitonclick()
if __name__ == '__main__':
main()

 

posted @ 2020-07-15 23:09  一个土豆芽  阅读(457)  评论(0编辑  收藏  举报