随笔分类 -  html

jquery ajax return jsonresult pattern
摘要：//javascriptvar queryParams = { "userId": userId, "factoryId": factoryId };$.ajax({ type: "POST", //默认是GET url: "/Home/SubmitToProcessed", data: query 阅读全文
posted @ 2017-07-26 10:54 kting 阅读(230) 评论(0) 推荐(0)