实验4

#include <stdio.h>
#define N 4
int main()
{
int a[N] = {2, 0, 2, 2};
char b[N] = {'2', '0', '2', '2'};
int i;
printf("sizeof(int) = %d\n", sizeof(int));
printf("sizeof(char) = %d\n", sizeof(char));
printf("\n");

for (i = 0; i < N; ++i)
printf("%p: %d\n", &a[i], a[i]);
printf("\n");

for (i = 0; i < N; ++i)
printf("%p: %c\n", &b[i], b[i]);
printf("\n");

printf("a = %p\n", a);
printf("b = %p\n", b);
return 0;
}

 

 

1.int型数组a，在内存单元中连续存放，每个元素占用4个内存字节单元。

2.char型数组b，在内存单元中连续存放，每个元素占用1个内存字节单元。

3.数组名a对应的值和&a[0]一样,数组名b对应的值和&b[0]一样.

 

#include <stdio.h>
#define N 2
#define M 3
int main()
{
int a[N][M] = {{1, 2, 3}, {4, 5, 6}};
char b[N][M] = {{'1', '2', '3'}, {'4', '5', '6'}};
int i, j;

for (i = 0; i < N; ++i)
for (j = 0; j < M; ++j)
printf("%p: %d\n", &a[i][j], a[i][j]);

printf("\n");

for (i = 0; i < N; ++i)
for (j = 0; j < M; ++j)
printf("%p: %c\n", &b[i][j], b[i][j]);

return 0;
}

 

 

1.按行连续存放，每个元素占用4个内存字节单元。

2.按行连续存放，每个元素占用1个内存字节单元。

#include<stdio.h>
int days_of_year(int year,int month,int day);
int main()
{
int year,month,day;
int days;
while(scanf("%d%d%d",&year,&month,&day) != EOF)
{
days = days_of_year(year,month,day);
printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days);

}
return 0;
}
int days_of_year(int year,int month,int day)
{
int s=0;
switch(month-1)
{
case 11:s+=30;
case 10:s+=31;
case 9:s+=30;
case 8:s+=31;
case 7:s+=31;
case 6:s+=30;
case 5:s+=31;
case 4:s+=30;
case 3:s+=31;
case 2:{
if((year%4==0&&year%100!=0)||year%400==0)
s+=29;
else
s+=28;
case 1:s+=31;
case 0:s+=0;
break;
}
}

return (s+day);
}

 

 

#include <stdio.h>
#define N 5
void input(int x[], int n);
void output(int x[], int n);
double average(int x[], int n);
void sort(int x[], int n);
int main()
{
int scores[N];
double ave;
printf("录入%d个分数:\n", N);
input(scores, N);
printf("\n输出课程分数: \n");
output(scores, N);
printf("\n课程分数处理: 计算均分、排序...\n");
ave = average(scores, N);
sort(scores, N);
printf("\n输出课程均分: %.2f\n", ave);
printf("\n输出课程分数(高->低):\n");
output(scores, N);
return 0;
}
void input(int x[],int n)
{
int i;
for(i=0;i<n;i++)
scanf("%d",&x[i]);
}
void output(int x[],int n)
{
int i;
for(i=0;i<n;i++)
printf("%d ",x[i]);
printf("\n");
}
double average(int x[],int n)
{
double s=0;
int i;
for(i=0;i<n;i++)
s+=x[i];

return (s/n);
}
void sort(int x[],int n)
{
int i,j,t;
for(j=0;j<n-1;j++)
{
for(i=0;i<n-1-j;i++)
{
if(x[i]>x[i+1])
{
t=x[i];
x[i]=x[i+1];
x[i+1]=t;
}
}

}
for(i=0;i<=n/2;i++)
{
t=x[i];
x[i]=x[n-i-1];
x[n-i-1]=t;
}
}

 

 

#include<stdio.h>
void dec2n(int x,int n);

int main()
{
int x;
printf("输入一个十进制整数：");
scanf("%d",&x);

dec2n(x,2);
dec2n(x,8);
dec2n(x,16);

return 0;
}
void dec2n(int x,int n)
{
int t,i,j;
int a[10086];
while(x!=0)
{
t=x%n;
a[i]=t;
x=x/n;
i++;
}
for(j=i-1;j>=0;j--)
{

if(a[j]>9&&a[j]<16)
{
printf("%c",a[j]-10+'A');
}
else
{
printf("%d",a[j]);
}
}
printf("\n");
}

 

 

#include<stdio.h>

int main()

{
int i,j,k,n;
printf(" Enter n: ");
while(scanf("%d",&n)!= EOF)
{
for(i=1;i<=n;i++)
{
for(j=1;j<=n;j++)
{
k=i>j?j:i;
printf("%3d",k);
}
printf("\n");
}
printf(" Enter n: ");
}
return 0;
}

 

 

#include<stdio.h>
#define N 80
int main()
{
char views1[N] = " hey, c, i hate u.";
char views2[N] = " hey, c, i love u.";
int i;
char t;
printf("original views:\n");
printf("views1:");
puts(views1);
printf("views2:");
puts(views2);
for (i = 0; views1[i]!= '\0'; i++)
{
t = views1[i];
views1[i] = views2[i];
views2[i] = t;
}
printf("\nswapping...\n\n");
printf("views1:");
puts(views1);
printf("views2:");
puts(views2);
return 0;
}

 

 

 

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>
#define N 5
#define M 20
void bubble_sort(char str[][M], int n);
int main()
{
char name[][M] = { "Bob", "Bill", "Joseph", "Taylor", "George" };
int i;
printf("输出初始名单:\n");
for (i = 0; i < N; i++)
printf("%s\n", name[i]);

printf("\n排序中...\n");
bubble_sort(name, N);

printf("\n按字典序输出名单:\n");
for (i = 0; i < N; i++)
printf("%s\n", name[i]);
return 0;
}
void bubble_sort(char str[][M], int n)
{
int i, j;
char a[M];
for (i = 0; i < N; i++)
{
for (j = 0; j < N - 1; j++)
{
if (strcmp(str[j], str[j + 1]) > 0)
{
strcpy(a, str[j]);
strcpy(str[j], str[j + 1]);
strcpy(str[j + 1], a);

}

}
}

}