Codeforces 672

题目链接:http://codeforces.com/contest/672/problem

A. Summer Camp(打表)

题意:123456789...一串字符串,问第n个是什么数字。

塞一个表进去。

 1 /*
 2 ━━━━━┒ギリギリ♂ eye!
 3 ┓┏┓┏┓┃キリキリ♂ mind!
 4 ┛┗┛┗┛┃\○/
 5 ┓┏┓┏┓┃ /
 6 ┛┗┛┗┛┃ノ)
 7 ┓┏┓┏┓┃
 8 ┛┗┛┗┛┃
 9 ┓┏┓┏┓┃
10 ┛┗┛┗┛┃
11 ┓┏┓┏┓┃
12 ┛┗┛┗┛┃
13 ┓┏┓┏┓┃
14 ┃┃┃┃┃┃
15 ┻┻┻┻┻┻
16 */
17 #include <algorithm>
18 #include <iostream>
19 #include <iomanip>
20 #include <cstring>
21 #include <climits>
22 #include <complex>
23 #include <fstream>
24 #include <cassert>
25 #include <cstdio>
26 #include <bitset>
27 #include <vector>
28 #include <deque>
29 #include <queue>
30 #include <stack>
31 #include <ctime>
32 #include <set>
33 #include <map>
34 #include <cmath>
35 using namespace std;
36 #define fr first
37 #define sc second
38 #define cl clear
39 #define BUG puts("here!!!")
40 #define W(a) while(a--)
41 #define pb(a) push_back(a)
42 #define Rint(a) scanf("%d", &a)
43 #define Rll(a) scanf("%I64d", &a)
44 #define Rs(a) scanf("%s", a)
45 #define Cin(a) cin >> a
46 #define FRead() freopen("in", "r", stdin)
47 #define FWrite() freopen("out", "w", stdout)
48 #define Rep(i, len) for(int i = 0; i < (len); i++)
49 #define For(i, a, len) for(int i = (a); i < (len); i++)
50 #define Cls(a) memset((a), 0, sizeof(a))
51 #define Clr(a, x) memset((a), (x), sizeof(a))
52 #define Fuint(a) memset((a), 0x7f7f, sizeof(a))
53 #define lrt rt << 1
54 #define rrt rt << 1 | 1
55 #define pi 3.14159265359
56 #define RT return
57 #define lowbit(x) x & (-x)
58 #define onenum(x) __builtin_popcount(x)
59 typedef long long LL;
60 typedef long double LD;
61 typedef unsigned long long Uint;
62 typedef pair<int, int> pii;
63 typedef pair<string, int> psi;
64 typedef map<string, int> msi;
65 typedef vector<int> vi;
66 typedef vector<int> vl;
67 typedef vector<vl> vvl;
68 typedef vector<bool> vb;
69 
70 int n;
71 string t = "0123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106107108109110111112113114115116117118119120121122123124125126127128129130131132133134135136137138139140141142143144145146147148149150151152153154155156157158159160161162163164165166167168169170171172173174175176177178179180181182183184185186187188189190191192193194195196197198199200201202203204205206207208209210211212213214215216217218219220221222223224225226227228229230231232233234235236237238239240241242243244245246247248249250251252253254255256257258259260261262263264265266267268269270271272273274275276277278279280281282283284285286287288289290291292293294295296297298299300301302303304305306307308309310311312313314315316317318319320321322323324325326327328329330331332333334335336337338339340341342343344345346347348349350351352353354355356357358359360361362363364365366367368369370371372373374375376377378379380381382383384385386387388389390391392393394395396397398399";
72 int main() {
73     // FRead();
74     while(~Rint(n)) {
75         printf("%d\n", t[n]-'0');
76     }
77     RT 0;
78 }
A

 

B. Different is Good(构造,胡搞)

题意:给一个数字n和一个字符串s,s中含有n个不同的字符,要求出现的所有字串的子串都不同,问最少修改字符串中多少个字符。

显然长度为1的子串想不同的话,必须每个字符都不同。所以当n>26的时候不可行;统计所有字符出现次数-1就是需要修改的字符数,修改次数超过26也是不允许的。

 1 /*
 2 ━━━━━┒ギリギリ♂ eye!
 3 ┓┏┓┏┓┃キリキリ♂ mind!
 4 ┛┗┛┗┛┃\○/
 5 ┓┏┓┏┓┃ /
 6 ┛┗┛┗┛┃ノ)
 7 ┓┏┓┏┓┃
 8 ┛┗┛┗┛┃
 9 ┓┏┓┏┓┃
10 ┛┗┛┗┛┃
11 ┓┏┓┏┓┃
12 ┛┗┛┗┛┃
13 ┓┏┓┏┓┃
14 ┃┃┃┃┃┃
15 ┻┻┻┻┻┻
16 */
17 #include <algorithm>
18 #include <iostream>
19 #include <iomanip>
20 #include <cstring>
21 #include <climits>
22 #include <complex>
23 #include <fstream>
24 #include <cassert>
25 #include <cstdio>
26 #include <bitset>
27 #include <vector>
28 #include <deque>
29 #include <queue>
30 #include <stack>
31 #include <ctime>
32 #include <set>
33 #include <map>
34 #include <cmath>
35 using namespace std;
36 #define fr first
37 #define sc second
38 #define cl clear
39 #define BUG puts("here!!!")
40 #define W(a) while(a--)
41 #define pb(a) push_back(a)
42 #define Rint(a) scanf("%d", &a)
43 #define Rll(a) scanf("%I64d", &a)
44 #define Rs(a) scanf("%s", a)
45 #define Cin(a) cin >> a
46 #define FRead() freopen("in", "r", stdin)
47 #define FWrite() freopen("out", "w", stdout)
48 #define Rep(i, len) for(int i = 0; i < (len); i++)
49 #define For(i, a, len) for(int i = (a); i < (len); i++)
50 #define Cls(a) memset((a), 0, sizeof(a))
51 #define Clr(a, x) memset((a), (x), sizeof(a))
52 #define Fuint(a) memset((a), 0x7f7f, sizeof(a))
53 #define lrt rt << 1
54 #define rrt rt << 1 | 1
55 #define pi 3.14159265359
56 #define RT return
57 #define lowbit(x) x & (-x)
58 #define onenum(x) __builtin_popcount(x)
59 typedef long long LL;
60 typedef long double LD;
61 typedef unsigned long long Uint;
62 typedef pair<int, int> pii;
63 typedef pair<string, int> psi;
64 typedef map<string, int> msi;
65 typedef vector<int> vi;
66 typedef vector<int> vl;
67 typedef vector<vl> vvl;
68 typedef vector<bool> vb;
69 
70 const int maxn = 100100;
71 int n;
72 char s[maxn];
73 int vis[256];
74 
75 int main(int argc, char const *argv[]) {
76     // FRead();
77     while(~Rint(n)) {
78         Cls(vis);
79         Rs(s);
80         if(n > 26) {
81             printf("-1\n");
82             continue;
83         }
84         for(int i = 0; s[i]; i++) {
85             vis[s[i]]++;
86         }
87         int ret = 0;
88         Rep(i, 256) {
89             if(vis[i] > 1) ret += vis[i] - 1;
90         }
91         if(ret > 26) printf("-1\n");
92         else printf("%d\n", ret);
93     }
94     return 0;
95 }
B

 

posted @ 2016-05-31 20:56  Kirai  阅读(187)  评论(0编辑  收藏  举报