
/* (a-c)×(d-c)*(d-c)×(b-c)>=0&&(c-a)×(b-a)*(b-a)×(d-a)>= 0就可以判断ab,cd相交*/
/* p1×p2 = x1y2 - x2y1 = - p2×p1-----(叉乘公式)叉积*/
#include<stdio.h>
struct point
{
double x,y;
};
//struct point a,b,c,d;
int mp(point a,point b,point c,point d){
double C=(a.x-c.x)*(d.y-c.y)-(d.x-c.x)*(a.y-c.y);
double D=(d.x-c.x)*(b.y-c.y)-(b.x-c.x)*(d.y-c.y);
if(C*D<0) return 0;
else return 1;
}
bool check(point a , point b , point c , point d){
if(!mp(a,b,c,d)) return false;
if(!mp(c,d,a,b)) return false;
return true;
}
int main(){
int T;
scanf("%d",&T);
while(T--){
point a,b,c,d;
scanf("%lf%lf%lf%lf%lf%lf%lf%lf",&a.x,&a.y,&b.x,&b.y,&c.x,&c.y,&d.x,&d.y);
if(check(a,b,c,d))
printf("Yes\n");
else
printf("No\n");
}
}