稀疏数组

package Array;
//稀疏数组
public class Demon6 {
public static void main(String[] args) {
//创建一个二维表11*11 0代表没有棋子,1代表黑旗,2代表白棋
int[][] array1 = new int[11][11];
array1[1][2] = 1;
array1[2][3] = 2;
//输出原始的数组
System.out.println("输出原始数组");

for (int[] ints : array1) {
for (int anInt : ints) {
System.out.print(anInt + " ");
}
System.out.println();
}
System.out.println("------------");
//转换为稀疏数组保存
//获取有效值得个数
int sum = 0;
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (array1[i][j] != 0) {
sum++;
}
}
}
System.out.println("有效值得个数:" + sum);
//2.创建一个稀疏数组的数组
int[][] array2 = new int[sum + 1][3];//sum+1代表行,3就是3列
array2[0][0] = 11;//11行
array2[0][1] = 11;//11列
array2[0][2] = sum;//个数
//遍历二维数组,将非零的值,存放稀疏数组中
int count = 0;
for (int i = 0; i < array1.length; i++) {
for (int j = 0; j < array1[1].length; j++) {
if (array1[i][j] != 0) {
count++;
array2[count][0] = i;//在第count行存放第0行为i
array2[count][1] = j;//在第count行存放第1行为j
array2[count][2] = array1[i][j];//值
}
}
}
//输出稀疏数组
System.out.println("稀疏数组");
for (int i = 0; i < array2.length; i++) {
System.out.println(array2[i][0] + " "
+ array2[i][1] + " "
+ array2[i][2] + "");
}
System.out.println("===============");
System.out.println("还原");
//1.读取稀疏数组
int[][] array3 = new int[array2[0][0]][array2[0][1]];//array2[0][0]为横坐标[array2[0][1]为纵坐标
//2.给其他的元素还原它的值
for (int i = 1; i < array2.length; i++) {
array3[array2[i][0]][array2[i][1]] = array2[i][2];
}
//3.打印
System.out.println("输出还原的数组");
for (int[] ints : array3) {
for (int anInt : ints) {
System.out.print(anInt + " ");
}
System.out.println();
}
}

结果:


输出原始数组
0 0 0 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0
0 0 0 2 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
------------
有效值得个数:2
稀疏数组
11 11 2
1 2 1
2 3 2
===============
还原
输出还原的数组
0 0 0 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0
0 0 0 2 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0

posted @ 2022-02-15 21:31  唐肖  阅读(25)  评论(0)    收藏  举报