表单元素提交时ＪＳ判断输入的值为空时则不刷新页面返回，不为空跳转并传值到新页面 

 <body>
           <div id="div1" style="display:block;" >
                         <div id="logo"></div>
                         <div id="word1"></div>
                         <div id="word2"></div>
                         <form name="form1" method="get"  action="zhengshu.php" onsubmit="return submitCheck();"> -----重点return +函数名实现为空返回原界面------------
                           <div  id="username">
                                  <div id="content">
                                       <input type="text" name="user" id="user"  class="bgc" autofocus="autofocus" placeholder="您的姓名" />
                                       <div><img src="images/word3.svg" /></div>
                                  </div>
                           </div> 
                         <input type="submit" id="sub" value="提交"></div>
                         </form>
          </div>
   
   </body>
      <script type="text/javascript">
 function submitCheck(){
            var txt = document.getElementById("user");
            if(txt.value==""){
            alert("请输入您的姓名");
            txt.focus();
            return false;   
           }
            return true;
  }
      </script>
<?php 
      $username=$_GET['user']; -------接收传过来的值
     
?>


 <div id="link"><?php echo $username ?></div>-----输出传过来的值

 

posted @ 2015-11-27 15:28  骏码信息  阅读(2175)  评论(0)    收藏  举报