C语言数组

练习一

#include<stdio.h>

void main() {
	int i,
		a[5] = {1,2,3},
		b[5];
	printf("\narray a is:");
	for (i = 0; i < 5; i++)
	{
		printf("%6d",a[i]);		// 	1	2	3	0	0
	}

	printf("\narray b is:");
	for (i = 0; i < 5; i++)
	{
		printf("%6d",b[i]);		//-858993460	-858993460	-858993460	-858993460	-858993460
	}

}

cpp

#include<iostream>
using namespace std;

int Fn(int n) {
	return n + 1;
}

int main() {
	int sum = Fn(2);
	cout << sum << endl;
	return 0;
}

斐切什么数列?

#include<stdio.h>

void main() {
	/*int n;
	printf("input numbers:\n");
	scanf("%d",&n);*/

	int i,
		a[20] = {1,1};
	for (i = 2; i < 20; i++)
	{
		a[i] = a[i - 1] + a[i - 2];
	}

	//打印
	for (i = 0; i < 20; i++)
	{
		if (0 == i % 5) {
			printf("\n");
		}

		printf("%12d",a[i]);
	}
	printf("\n");
}