25~~

int k;
scanf("%d", &k);
int x[100];
for (int i = 0; i < k; ++i)
scanf("%d", &x[i]);
int count1 = 0, count5 = 0, count10 = 0;
for (int i = 0; i < k; ++i)
{
int num = x[i];
if (num == 1)
count1++;
else if (num == 5)
count5++;
else if (num == 10)
count10++;
}
printf("%d %d %d\n", count1, count5, count10);
return 0;
}

收获:pass,pass

posted @ 2025-07-05 10:36  ervgiu28hg34y827  阅读(10)  评论(0)    收藏  举报