U

int n,j,y,t,j2,y2,t2,x,w,z;//j,y,t:金牌,银牌,铜牌
scanf("%d", &n);
j= n/10;
y=(n20)/100;
t=(n
30)/100;
j2=(n10+99)/100;
y2=(n
20+99)/100;
t2=(n*30+99)/100;
x=j2-j;
w=y2-(y-x);
z=t2-(t-w);

printf("%d %d %d\n", x,w,z);
return 0;

posted @ 2025-06-24 22:04  ervgiu28hg34y827  阅读(9)  评论(0)    收藏  举报