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【mysql】 查询数据时group by,及group_concat()函数用法

GROUP BY 语句

语法

        select 
            聚合函数,
            列(要求出现在group by的后面)
        fromwhere 
            筛选条件
        group by 
            分组的列表
        order by 
            子句

注意:除了出现在group by后面的字段,如果要在select后查询其他字段,必须用聚合函数进行聚合

特点:分组查询中的筛选条件分为两类:
分组前筛选: 数据源是原始表,用where,放在group by前面,因为在分组前筛选
分组后筛选:数据源是分组后的结果集 ,用having,放在group by后面,因为在分组后进行筛选。

例子

# 查询每个工种最高工资员工
select 
    max(salary),
    job_id
from 
    employees
group by 
    job_id;



# 查询邮箱中包含a字符的每个部门的平均工资
select 
    avg(salary),
    department_id
from 
    employees
where 
    email like '%a%'
group by 
    department_id



# 查询有奖金的每个领导手下最高工资的员工工资
select 
    max(salary),
    manager_id 
from 
    employees
where 
    commission_pct is not null
group by 
    manager_id



# 查询哪个部门的员工个数大于2
select  
    count(*),
    department_id 
from 
    employees 
group by 
    department_id 
having 
    count(*) > 2;



# 查询每个工种有奖金的员工的最高工资大于12000的工种编号和最高工资
select 
    max(salary),
    job_id
from 
    employees
where 
    commission_pct is not null
group by 
    job_id 
having 
    max(salary) > 12000;

 

按表达式或聚合函数进行筛选

# 按照员工姓名长度分组,查询每一组员工个数,筛选员工个数大于5的有哪些
select 
    count(*)  ,
    length(last_name) as len_name
from 
    employees 
group by 
    length(last_name)
having 
    count(*) > 5;

 

按照多个字段分组

# 查询每个部门每个工种的员工平均工资,并且按照平均工资的高低排序
select 
    avg(salary),
    department_id,
    job_id 
from 
    employees
where 
    department_id is not null
group by 
    department_id,
    job_id
order by 
    avg(salary) desc;

 

group_concat()函数

group_concat()函数语法如下:

group_concat([DISTINCT] 要连接的字段 [Order BY ASC/DESC 排序字段] [Separator '分隔符'])

示例:SELECT * FROM testgroup

表结构与数据如上

现在的需求就是每个id为一行 在前台每行显示该id所有分数

  • SELECT id,GROUP_CONCAT(score) FROM testgroup GROUP BY id

可以看到 根据id 分成了三行 并且分数默认用 逗号 分割 但是有每个id有重复数据

 

接下来去重:

  •  SELECT id,GROUP_CONCAT(DISTINCT score) FROM testgroup GROUP BY id

 

 

排序:

  • SELECT id,GROUP_CONCAT(DISTINCT score ORDER BY score DESC) as result FROM testgroup GROUP BY id

 

最后可以设置分隔符:

  • SELECT id,GROUP_CONCAT(DISTINCT score ORDER BY score DESC SEPARATOR '-') as result FROM testgroup GROUP BY id

 

reference

https://www.cnblogs.com/tff612/p/15513606.html

https://blog.csdn.net/weixin_41885239/article/details/115933896

posted @ 2023-02-01 10:24  走位,走位  阅读(653)  评论(0编辑  收藏  举报