ForkJoin

ForkJoin

ForkJoin 在 JDK 1.7 , 并行执行任务!提高效率。
大数据量! 大数据:Map Reduce (把大任务拆分为小任务)

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  • ForkJoin 特点:工作窃取

    这个里面维护的都是双端队列

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ForkJoinPool

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image-20200804111006757

/**
 * 求和计算的任务!
 * 3000   6000(ForkJoin)  9000(Stream并行流)
 * // 如何使用 forkjoin
 * // 1、forkjoinPool 通过它来执行
 * // 2、计算任务 forkjoinPool.execute(ForkJoinTask task)
 * // 3. 计算类要继承 ForkJoinTask
 */
public class ForkJoinDemo extends RecursiveTask<Long> {

    private Long start;  // 1
    private Long end;    // 1990900000

    // 临界值
    private Long temp = 10000L;

    public ForkJoinDemo(Long start, Long end) {
        this.start = start;
        this.end = end;
    }

    // 计算方法
    @Override
    protected Long compute() {
        if ((end-start)<temp){
            Long sum = 0L;
            for (Long i = start; i <= end; i++) {
                sum += i;
            }
            return sum;
        }else { // forkjoin 递归
            long middle = (start + end) / 2; // 中间值
            ForkJoinDemo task1 = new ForkJoinDemo(start, middle);
            task1.fork(); // 拆分任务,把任务压入线程队列
            ForkJoinDemo task2 = new ForkJoinDemo(middle+1, end);
            task2.fork(); // 拆分任务,把任务压入线程队列

            return task1.join() + task2.join();
        }
    }
}

测试:

public class Test {
    public static void main(String[] args) throws ExecutionException, InterruptedException {
         test1(); // 6926
         test2(); // 4482
         test3(); // 174
    }

    // 普通程序员
    public static void test1(){
        Long sum = 0L;
        long start = System.currentTimeMillis();
        for (Long i = 1L; i <= 10_0000_0000; i++) {
            sum += i;
        }
        long end = System.currentTimeMillis();
        System.out.println("sum="+sum+" 时间:"+(end-start));
    }

    // 会使用ForkJoin
    public static void test2() throws ExecutionException, InterruptedException {
        long start = System.currentTimeMillis();

        ForkJoinPool forkJoinPool = new ForkJoinPool();
        ForkJoinTask<Long> task = new ForkJoinDemo(0L, 10_0000_0000L);
        ForkJoinTask<Long> submit = forkJoinPool.submit(task);// 提交任务
        Long sum = submit.get();

        long end = System.currentTimeMillis();

        System.out.println("sum="+sum+" 时间:"+(end-start));
    }

    public static void test3(){
        long start = System.currentTimeMillis();
        // Stream并行流 ()  (]
        long sum = LongStream.rangeClosed(0L, 10_0000_0000L).parallel().reduce(0, Long::sum);
        long end = System.currentTimeMillis();
        System.out.println("sum="+"时间:"+(end-start));
    }

}

视频参考https://www.bilibili.com/video/BV1B7411L7tE
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posted @ 2020-08-05 22:44  Maple_XL  阅读(86)  评论(0编辑  收藏  举报