interleaving string 

 1 class Solution {
 2 
 3 public:
 4     bool isInterleave(string s1, string s2, string s3) {
 5         // Start typing your C/C++ solution below
 6         // DO NOT write int main() function 
 7         if (s1.size() + s2.size() != s3.size())
 8             return false;
 9         
10         vector< vector<bool>> f(s1.size()+1,vector<bool>(s2.size()+1,false));
11         f[0][0] = true;
12         for(int i = 1; i <= s1.size(); i++)
13             f[i][0] = f[i-1][0] && (s3[i-1] == s1[i-1]);
14             
15         for(int j = 1; j <= s2.size(); j++)
16             f[0][j] = f[0][j-1] && (s3[j-1] == s2[j-1]);
17             
18         for(int i = 1; i <= s1.size(); i++)
19             for(int j = 1; j <= s2.size(); j++)
20                 f[i][j] = (f[i][j-1] && s2[j-1] == s3[i+j-1]) || (f[i-1][j] && s1[i-1] == s3[i+j-1]);
21                 
22         return f[s1.size()][s2.size()];
23     }
24 };

 

posted on 2013-09-06 12:34  jumping_grass  阅读(155)  评论(0)    收藏  举报

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