Sql 连续性提交

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declare

row_num number := 0;

begin

for gyj_test in(select id from gyj_test1 t where xx is null) loop

delete from gyj_test1 where id=gyj_test.id;

row_num := row_num +1;

---2000条提交一次,可根据需要修改

if mod(row_num,2000) = 0 then

commit;

end if;

end loop;

commit;

end;



declare @min int
declare @max int
declare @actid NUMERIC

set @min=0 --从0开始
set @max=300 --循环次数
set @actid= 1000000003228041

while @min<@max

BEGIN

waitfor delay '00:00:03'

delete FROM plan_scst WHERE fscprdid = '1912' AND actid <=@actid

set @min=@min+1
set @actid=@actid+5000
SELECT @min --打印执行结果

END

 

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posted @ 2021-04-07 11:18  茶叶蛋蛋  阅读(91)  评论(0)    收藏  举报