go interface{}使用

先上代码

func In(haystack []interface{}, needle interface{}) (bool, error) {
	sVal := reflect.ValueOf(haystack)
	kind := sVal.Kind()
	if kind == reflect.Slice || kind == reflect.Array {
		for i := 0; i < sVal.Len(); i++ {
			if sVal.Index(i).Interface() == needle {
				return true, nil
			}
		}
		return false, nil
	}
	return false, fmt.Errorf("UnSupportType")
}

func test() {
    a := []int{1,2}
    b := 3
    flag, err := In(a,b)    // error, cannot user 'a'(type []int) as type []interface{}
}

　　

为什么会报错？

因为空接口拥有两个指针，内存布局上会占用两个机器字长。

对于长度为n的空接口切片而言，它的每个元素都是以2机器字长为单位的连续空间，因此总共会占用 2n个机器字长的空间。然而对于普通的切片，[]int它的每个元素都是 int 类型的，由于 []int 和 []interface{} 内存布局不同，所以不能直接将 []int 作为 []interface{};

 

Introduction
 
Given that you can assign a variable of any type to an interface{}, often people will try code like the following.
 
var dataSlice []int = foo()
var interfaceSlice []interface{} = dataSlice
This gets the error
 
cannot use dataSlice (type []int) as type []interface { } in assignment
The question then, "Why can't I assign any slice to an []interface{}, when I can assign any type to an interface{}?"
 
Why?
 
There are two main reasons for this.
 
The first is that a variable with type []interface{} is not an interface! It is a slice whose element type happens to be interface{}. But even given this, one might say that the meaning is clear.
 
Well, is it? A variable with type []interface{} has a specific memory layout, known at compile time.
 
Each interface{} takes up two words (one word for the type of what is contained, the other word for either the contained data or a pointer to it). As a consequence, a slice with length N and with type []interface{} is backed by a chunk of data that is N*2 words long.
 
This is different than the chunk of data backing a slice with type []MyType and the same length. Its chunk of data will be N*sizeof(MyType) words long.
 
The result is that you cannot quickly assign something of type []MyType to something of type []interface{}; the data behind them just look different.
 
What can I do instead?
 
It depends on what you wanted to do in the first place.
 
If you want a container for an arbitrary array type, and you plan on changing back to the original type before doing any indexing operations, you can just use an interface{}. The code will be generic (if not compile-time type-safe) and fast.
If you really want a []interface{} because you'll be doing indexing before converting back, or you are using a particular interface type and you want to use its methods, you will have to make a copy of the slice.
var dataSlice []int = foo()
var interfaceSlice []interface{} = make([]interface{}, len(dataSlice))
for i, d := range dataSlice {
    interfaceSlice[i] = d
}