实验6
实验任务4
task4.c
源代码
#include <stdio.h>
#define N 10
typedef struct {
char isbn[20];
char name[80];
char author[80];
double sales_price;
int sales_count;
} Book;
void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);
int main() {
Book x[N] = {
{"978-7-5327-6082-4", "门将之死", "罗纳德·伦", 42, 51},
{"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
{"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
{"978-7-5447-5246-6", "软体体的生命周期", "特德姜", 35, 90},
{"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
{"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
{"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
{"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
{"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5,55},
{"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}
};
printf("图书销量排名(按销售册数)：\n");
sort(x, N);
output(x, N);
printf("\n图书销售总额：%.2f\n", sales_amount(x, N));
return 0;
}
void output(Book x[], int n)
{
int i;
for(i = 0; i < n; i++)
{
printf("ISBN:%-20s 书名:%-20s 作者:%-12s 售价:%.2f 销量:%d\n",
x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);
}
}
void sort(Book x[], int n)
{
int i, j;
Book temp;
for(i = 0; i < n - 1; i++)
{
for(j = 0; j < n - 1 - i; j++)
{
if(x[j].sales_count < x[j+1].sales_count)
{
temp = x[j];
x[j] = x[j+1];
x[j+1] = temp;
}
}
}
}
double sales_amount(Book x[], int n)
{
int i;
double total = 0;
for(i = 0; i < n; i++)
{
total += x[i].sales_price * x[i].sales_count;
}
return total;
}运行截图
实验任务5
task5.c
源代码
#include <stdio.h>
typedef struct {
int year;
int month;
int day;
} Date;
void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1, Date d2);
void test1() {
Date d;
int i;
printf("输入日期:(以形如2025-12-19这样的形式输入)\n");
for(i = 0; i < 3; ++i)
{
input(&d);
int num = day_of_year(d);
printf("%d-%02d-%02d是这一年中第%d天\n", d.year, d.month, d.day, num);
}
}
void test2() {
Date Alice_birth, Bob_birth;
int i;
int ans;
printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n");
for(i = 0; i < 3; ++i)
{
input(&Alice_birth);
input(&Bob_birth);
ans = compare_dates(Alice_birth, Bob_birth);
if(ans == 0)
printf("Alice和Bob一样大\n\n");
else if(ans == -1)
printf("Alice比Bob大\n\n");
else
printf("Alice比Bob小\n\n");
}
}
int main() {
printf("测试1：输入日期，打印输出这一年中第多少天\n");
test1();
printf("\n测试2：两个人年龄大小关系\n");
test2();
return 0;
}
void input(Date *pd) {
scanf("%d-%d-%d", &pd->year, &pd->month, &pd->day);
}
int day_of_year(Date d) {
int mon_days[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
int sum = 0;
for(int i = 0; i < d.month - 1; i++)
{
sum += mon_days[i];
}
sum += d.day;
if((d.year % 4 == 0 && d.year % 100 != 0) || (d.year % 400 == 0))
{
if(d.month > 2)
sum++;
}
return sum;
}
int compare_dates(Date d1, Date d2) {
if(d1.year < d2.year)
return -1;
else if(d1.year > d2.year)
return 1;
if(d1.month < d2.month)
return -1;
else if(d1.month > d2.month)
return 1;
if(d1.day < d2.day)
return -1;
else if(d1.day > d2.day)
return 1;
return 0;
}运行截图
实验任务6
task6.c
源代码
#include <stdio.h>
#include <string.h>
enum Role {admin, student, teacher};
typedef struct {
char username[20];
char password[20];
enum Role type;
} Account;
void output(Account x[], int n);
int main() {
Account x[] = {{"A1001", "123456", student},
{"A1002", "123abcdef", student},
{"A1009", "xyz12121", student},
{"X1009", "9213071x", admin},
{"c11553", "129dfg32k", teacher},
{"X3005", "921kfmg917", student}};
int n;
n = sizeof(x)/sizeof(Account);
output(x, n);
return 0;
}
void output(Account x[], int n) {
int i, k;
int len;
for(i = 0; i < n; i++)
{
len = strlen(x[i].password);
printf("用户名：%s，密码：", x[i].username);
for(k = 0; k < len; k++)
{
printf("*");
}
printf("，角色：");
switch(x[i].type)
{
case admin: printf("管理员\n");break;
case student: printf("学生\n");break;
case teacher: printf("教师\n");break;
}
}
}
运行截图
实验任务7
task7.c
源代码
#include <stdio.h>
#include <string.h>
#define N 10
typedef struct {
char name[20];
char phone[12];
int vip;
} Contact;
void set_vip_contact(Contact x[], int n, char name[]);
void output(Contact x[], int n);
void display(Contact x[], int n);
int comparePinyin(char *a, char *b)
{
char order[10][4]={"陈二","李四","刘一","孙八","王五","吴九","郑十","周七","张三","赵六"};
int posA,posB,i;
for(i=0;i<10;i++){
if(strcmp(a,order[i])==0) posA=i;
if(strcmp(b,order[i])==0) posB=i;
}
return posA - posB;
}
int main() {
Contact list[N] = {{"刘一", "15510846604", 0},
{"陈二", "18038747351", 0},
{"张三", "18853253914", 0},
{"李四", "13230584477", 0},
{"王五", "15547571923", 0},
{"赵六", "18856659351", 0},
{"周七", "17705843215", 0},
{"孙八", "15552933732", 0},
{"吴九", "18077702405", 0},
{"郑十", "18820725036", 0}};
int vip_cnt, i;
char name[20];
printf("显示原始通讯录信息：\n");
output(list, N);
printf("\n输入要设置的紧急联系人个数：");
scanf("%d", &vip_cnt);
printf("输入%d个紧急联系人姓名:\n", vip_cnt);
for(i = 0; i < vip_cnt; i++)
{
scanf("%s", name);
set_vip_contact(list, N, name);
}
printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
display(list, N);
return 0;
}
void set_vip_contact(Contact x[], int n, char name[])
{
int i;
for(i = 0; i < n; i++)
{
if(strcmp(x[i].name, name) == 0)
{
x[i].vip = 1;
break;
}
}
}
void output(Contact x[], int n)
{
int i;
for(i = 0; i < n; i++)
{
printf("%-10s%-15s", x[i].name, x[i].phone);
if(x[i].vip == 1)
printf("*\n");
else
printf("\n");
}
}
void display(Contact x[], int n)
{
int i, j;
Contact temp;
for(i = 0; i < n - 1; i++)
{
for(j = 0; j < n - 1 - i; j++)
{
//1. vip优先，1在前，0在后
if(x[j].vip < x[j+1].vip)
{
temp = x[j];
x[j] = x[j+1];
x[j+1] = temp;
}
else if(x[j].vip == x[j+1].vip)
{
if(comparePinyin(x[j].name, x[j+1].name) > 0)
{
temp = x[j];
x[j] = x[j+1];
x[j+1] = temp;
}
}
}
}
output(x,n);
}
运行截图
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