236. 二叉树的最近公共祖先


unordered_set哈希集合确实好像速度慢,还是我自己的问题
一遍遍历找到p结点的所有祖先,然后再后序遍历q结点的祖先
查看代码
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
unordered_set<TreeNode*>s;
find_parent_p(s,root,p);
TreeNode* temp = new TreeNode();
find_parent_q(s,root,q,temp);
return temp->left;
}
bool find_parent_p(unordered_set<TreeNode*>& s,TreeNode* root,TreeNode* p){
if(root == NULL){
return false;
}
if(root == p){
s.insert(root);
return true;
}
if(find_parent_p(s,root->left,p)||find_parent_p(s,root->right,p)){
s.insert(root);
return true;
}
else{
return false;
}
}
bool find_parent_q(unordered_set<TreeNode*>& s,TreeNode* root,TreeNode* q,TreeNode* temp){
if(root == NULL){
return false;
}
//cout<<root->val;
if(root == q){
if(s.count(root)!=0){
temp->left= root;
return false;
}
return true;
}
if(find_parent_q(s,root->left,q,temp)||find_parent_q(s,root->right,q,temp)){
if(s.count(root)!=0){
temp->left =root;
// cout<<root->val;
return false;
}
// cout<<root->val;
return true;
}
else
return false;
}
};

浙公网安备 33010602011771号