NYOJ33

模拟填数的过程

#include <cstdio>
#include <algorithm>
#include <cstring>
using namespace std;

void snake(int n) {
	int t = 1, tot = n*n; 
	int a[n][n]; //存储数据的二维数组
	int i = 0,j = n-1;  //两个动态变换的坐标,记录行走过程中的位置
	memset(a, 0, sizeof(a)); //二维数组不能直接赋值 a[n][n] = {0} 无效!! 
	a[i][j] = t++; 
	while (t <= tot) {
		while (i+1 < n && a[i+1][j] == 0) a[++i][j] = t++; //向下走
		while (j-1 >= 0 && a[i][j-1] == 0) a[i][--j] = t++; //向左走
		while (i-1 >= 0 && a[i-1][j] == 0) a[--i][j] = t++; //向上走
		while (j+1 < n && a[i][j+1] == 0) a[i][++j] = t++; //向右走
	}
	
	for (i = 0; i < n; i++) {
		for (j = 0; j < n; j++) 
			printf("%d ", a[i][j]);
		printf("\n");	
	}	
}

int main() {
	int n;
	scanf("%d", &n);
	snake(n);
	return 0;
} 

 

posted @ 2018-11-20 20:13  JonnyOu1012  阅读(23)  评论(0)    收藏  举报