package LeetCode_1202
import java.util.*
import kotlin.collections.HashMap
/**
* 1202. Smallest String With Swaps
* https://leetcode.com/problems/smallest-string-with-swaps/
* You are given a string s,
* and an array of pairs of indices in the string pairs where pairs[i] = [a, b] indicates 2 indices(0-indexed) of the string.
You can swap the characters at any pair of indices in the given pairs any number of times.
Return the lexicographically smallest string that s can be changed to after using the swaps.
Example 1:
Input: s = "dcab", pairs = [[0,3],[1,2]]
Output: "bacd"
Explaination:
Swap s[0] and s[3], s = "bcad"
Swap s[1] and s[2], s = "bacd"
Example 2:
Input: s = "dcab", pairs = [[0,3],[1,2],[0,2]]
Output: "abcd"
Explaination:
Swap s[0] and s[3], s = "bcad"
Swap s[0] and s[2], s = "acbd"
Swap s[1] and s[2], s = "abcd"
Example 3:
Input: s = "cba", pairs = [[0,1],[1,2]]
Output: "abc"
Explaination:
Swap s[0] and s[1], s = "bca"
Swap s[1] and s[2], s = "bac"
Swap s[0] and s[1], s = "abc"
Constraints:
1. 1 <= s.length <= 10^5
2. 0 <= pairs.length <= 10^5
3. 0 <= pairs[i][0], pairs[i][1] < s.length
4. s only contains lower case English letters.
* */
class Solution {
/*
* solution: UnionFind + HashMap + PriorityQueue, group by words which can connect each other,
* Time:O(nlogn), Space:O(n)
* */
fun smallestStringWithSwaps(s: String, pairs: List<List<Int>>): String {
val n = s.length
val unionFind = UnionFind(n)
for (item in pairs) {
unionFind.union(item[0], item[1])
}
val map = HashMap<Int, PriorityQueue<Char>>()
for (i in 0 until n) {
//check which group contains current i
val root = unionFind.find(i)
map.putIfAbsent(root, PriorityQueue())
//put in queue which in same group
map.get(root)!!.offer(s[i])
}
val sb = StringBuilder()
for (i in 0 until n) {
val root = unionFind.find(i)
//append current group's minimum char into result
sb.append(map.get(root)!!.poll())
}
return sb.toString()
}
}
class UnionFind constructor(n: Int) {
private var parent: IntArray? = null
init {
parent = IntArray(n)
for (i in 0 until n) {
parent!![i] = i
}
}
fun find(p: Int): Int {
if (parent!![p] != p) {
parent!![p] = find(parent!![p])
}
return parent!![p]
}
fun union(i: Int, j: Int) {
val parentI = find(i)
val parentJ = find(j)
if (parentI != parentJ) {
parent!![parentJ] = parentI
}
}
}