package _interview_question
/**
* Given a integer n, return all amicable paris
* */
class Solution16 {
/*
* solution: get sum of divisors of number,Time:O(nlogn), Space:O(1)
* 一对整数是相亲数是说他们各自的所有有效因子(除了自己以外的因子)之和等于另外一个数。比如 (220, 284) 就是一对相亲数。因为:
1. 220的所有因子:1+2+4+5+10+11+20+22+44+55+110 = 284
2. 284的所有因子:1+2+4+71+142 = 220
* */
fun amicablePairs(n: Int): List<List<Int>> {
val result = ArrayList<ArrayList<Int>>()
for (i in 1..n) {
val sum = getFactorsSum(i)
if (sum <= i || sum > n) {
continue
}
if (getFactorsSum(sum) == i) {
val pairs = ArrayList<Int>(2)
pairs.add(i)
pairs.add(sum)
result.add(pairs)
}
}
return result
}
/**
* calculate the sum of proper divisors
* */
private fun getFactorsSum(n: Int): Int {
var sum = 1
//Time:O(n)
/*for (i in 1..n) {
if (n % i == 0 && i != n) {
sum += i
}
}*/
//Time:O(logn)
var i = 2
while (i * i < n) {
if (n % i == 0) {
sum += i + n / i
}
i++
}
return sum
}
/**
* return the number of pairs in the array that form an amicable pair.
* */
private fun amicablePairsCount(array: IntArray): Int {
var count = 0
for (i in array.indices) {
for (j in i + 1 until array.size) {
if (isAmicablePairs(array[i], array[j])) {
count++
}
}
}
return count
}
private fun isAmicablePairs(a: Int, b: Int): Boolean {
return getFactorsSum(a) == b && getFactorsSum(b) == a
}
}