package LeetCode_69
/**
* 69. Sqrt(x)
* https://leetcode.com/problems/sqrtx/description/
*
* Implement int sqrt(int x).
Compute and return the square root of x, where x is guaranteed to be a non-negative integer.
Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.
Example 1:
Input: 4
Output: 2
Example 2:
Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since
the decimal part is truncated, 2 is returned.
* */
class Solution {
/*
* solution: Binary Search
* */
fun mySqrt(x: Int): Int {
var l = 0
var r = x
//close left and open right
while (l < r) {
val m = l + (r - l) / 2
if (m > x / m) {//<=m(g)
//new range:[l,m)
r = m
} else {
l = m + 1
}
}
//l is the first one large than Sqrt(x), so return l-1
return l - 1
}
}