package LeetCode_207
import java.util.*
import kotlin.collections.ArrayList
/**
* 207. Course Schedule
* https://leetcode.com/problems/course-schedule/description/
*
There are a total of numCourses courses you have to take, labeled from 0 to numCourses-1.
Some courses may have prerequisites, for example to take course 0 you have to first take course 1,which is expressed as a pair: [0,1]
Given the total number of courses and a list of prerequisite pairs, is it possible for you to finish all courses?
Example 1:
Input: numCourses = 2, prerequisites = [[1,0]]
Output: true
Explanation: There are a total of 2 courses to take.
Example 2:
Input: numCourses = 2, prerequisites = [[1,0],[0,1]]
Output: false
Explanation: There are a total of 2 courses to take.
To take course 1 you should have finished course 0, and to take course 0 you should
also have finished course 1. So it is impossible.
* */
class Solution {
/**
* solution: BFS
* Time complexity:O(n^2), Space complexity:O(n)
* */
fun canFinish(numCourses: Int, prerequisites: Array<IntArray>): Boolean {
val graph = ArrayList<ArrayList<Int>>()
//create graph by prerequisites
for (i in 0 until numCourses) {
graph.add(ArrayList())
}
for (item in prerequisites){
val start = item[1]
val end = item[0]
graph[start].add(end)
}
//calculate in degree
val indegrees = IntArray(numCourses)
for (g in graph){
for (item in g){
indegrees[item]++
}
}
val queue = LinkedList<Int>()
for (i in 0 until numCourses) {
if (indegrees[i]==0){
queue.offer(i)
}
}
while (queue.isNotEmpty()){
val cur = queue.poll()
for (item in graph[cur]){
indegrees[item]--
if (indegrees[item]==0){
queue.offer(item)
}
}
}
for (i in 0 until numCourses){
if (indegrees[i]!=0){
//represent graph got a cycle, so return false
return false
}
}
return true
}
}