package LeetCode_65
/**
* 65. Valid Number
* https://leetcode.com/problems/valid-number/description/
*
* Validate if a given string can be interpreted as a decimal number.
Some examples:
"0" => true
" 0.1 " => true
"abc" => false
"1 a" => false
"2e10" => true
" -90e3 " => true
" 1e" => false
"e3" => false
" 6e-1" => true
" 99e2.5 " => false
"53.5e93" => true
" --6 " => false
"-+3" => false
"95a54e53" => false
Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.
However, here is a list of characters that can be in a valid decimal number:
Numbers 0-9
Exponent - "e"
Positive/negative sign - "+"/"-"
Decimal point - "."
* */
class Solution {
fun isNumber(s: String): Boolean {
var eSeen = false
var dotSeen = false
var numSeen = false
val s2 = s.trim()
for (i in s2.indices) {
val c = s2[i]
if (c.isDigit()) {
numSeen = true
} else if (c == 'e') {
if (!numSeen || eSeen) {
return false
}
eSeen = true
//for example "1e" is not valid, so while e has seen, need set numSeen to false
numSeen = false
} else if (c == '.') {
if (dotSeen || eSeen) {
/*
* 1.dot cannot appear two times
* 2.just can appear after e, for example: 99e2.5 is not Valid
* */
return false
}
dotSeen = true
} else if (c == '+' || c == '-') {
if (i != 0 && s2[i - 1] != 'e') {
/*
* + and -
* 1.can appear in first position
* 2.if appear after e, is valid, for example: "005047e+6" is valid
* */
return false
}
} else {
//abc is not valid
return false
}
}
return numSeen
}
}