package LeetCode_224
import java.util.*
/**
* 224. Basic Calculator
* https://leetcode.com/problems/basic-calculator/description/
*
* Implement a basic calculator to evaluate a simple expression string.
The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces .
Example 1:
Input: "1 + 1"
Output: 2
Example 2:
Input: " 2-1 + 2 "
Output: 3
Example 3:
Input: "(1+(4+5+2)-3)+(6+8)"
Output: 23
Note:
You may assume that the given expression is always valid.
Do not use the eval built-in library function.
* */
class Solution {
private val operator = listOf("+", "-")
fun calculate(s: String): Int {
val stack = Stack<String>()
var i = s.length - 1
while (i >= 0) {
if (s[i]==' '){
i--
continue
}
if (s[i] == ')' || s[i] == '+' || s[i] == '-') {
stack.push(s[i].toString())
} else if (s[i] == '(') {
val sum = getSum(stack)
stack.pop()
stack.push(sum.toString())
} else {
val intSB = StringBuilder()
//pick out the digit, for example:10
while (i >= 0 && s[i].isDigit()) {
intSB.insert(0,s[i--])
}
i++//prevent lose some operator, so need go back, for example: 2-1 + 2
stack.push(intSB.toString())
}
i--
}
//result = getSum(stack)
return getSum(stack)
}
private fun getSum(stack: Stack<String>): Int {
var sign = "+"
var total = 0
while (stack.isNotEmpty() && stack.peek() != "(" && stack.peek() != ")") {
if (stack.peek() in operator) {
sign = stack.pop()
} else {
val temp = stack.pop().toInt()
total += if (sign == "+") temp else -temp
}
}
return total
}
}