获取url的参数

function getParams() { 
    let url = location.search
    let params={}
    if (url.indexOf("?") != -1) { 
        let str = url.substr(1)
        strs = str.split("&")
        for(var i = 0; i < strs.length; i ++) { 
　　    params[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1])
        } 
    } 
    return params
}