实验7

实验任务4:

#include <stdio.h>
#include <ctype.h>

int main() {
FILE *fp;
char ch;
int line_count = 0;
int char_count = 0;

fp = fopen("data4.txt", "r");
if (fp == NULL) {
printf("无法打开文件!\n");
return 1;
}

while ((ch = fgetc(fp)) != EOF) {
if (ch == '\n') {
line_count++;
}
if (!isspace(ch)) {
char_count++;
}
}
if (line_count > 0 || char_count > 0) {
line_count++;
}

printf("data4.txt统计结果:\n");
printf("行数:\t\t%d\n", line_count);
printf("字符数(不计空白符):\t%d\n", char_count);

fclose(fp);
return 0;
}3708053-20251230220229872-657421629

实验任务5:

#include <stdio.h>
#include <string.h>

#define N 10

typedef struct
{
long id; // 准考证号
char name[20]; // 姓名
float objective; // 客观题得分
float subjective; // 操作题得分
float sum; // 总分
char result[10]; // 考试结果
} STU;

// 函数声明
void read(STU st[], int n)
;
void write(STU st[], int n)
;
void output(STU st[], int n)
;
int process(STU st[], int n, STU st_pass[])
;

int main()
{
STU stu[N], stu_pass[N];
int
cnt;
double
pass_rate;

printf("从文件读入%d个考生信息...\n"
, N);
read
(stu, N);

printf("\n对考生成绩进行统计...\n"
);
cnt =
process
(stu, N, stu_pass);

printf("\n通过考试的名单:\n"
);
output(stu, N); // 输出所有考生完整信息到屏幕
write(stu, N); // 输出考试通过的考生信息到文件

pass_rate =
1.0
* cnt / N;
printf("\n本次等级考试通过率: %.2f%%\n", pass_rate*100
);

return 0
;
}

// 把所有考生完整信息输出到屏幕上
// 准考证号,姓名,客观题得分,操作题得分,总分,结果
void output(STU st[], int n)
{
int
i;

printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n"
);
for (i = 0
; i < n; i++)
printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n"
, st[i].id, st[i].name, st[i].objective, st[i].subjective, st[i].sum, st[i].result);
}

// 从文本文件examinee.txt读入考生信息:准考证号,姓名,客观题得分,操作题得分
void read(STU st[], int n)
{
int
i;
FILE *fin;

fin =
fopen("examinee.txt", "r"
);
if
(!fin) {
printf("fail to open file\n"
);
return
;
}

for (i = 0
; i < n; i++)
fscanf(fin, "%ld %s %f %f"
, &st[i].id, st[i].name, &st[i].objective, &st[i].subjective);

fclose
(fin);
}

// 把通过考试的考生完整信息写入文件list_pass.txt
// 准考证号,姓名,客观题得分,操作题得分,总分,结果
void write(STU s[], int n)
{
int
i;
FILE *fp;

fp =
fopen("list_pass.txt", "w"
);
if(fp == NULL
) {
printf("fail to open file to write\n"
);
return
;
}

fprintf(fp,"准考证号\t姓名\t\t客观题得分\t\t主观题得分\t\t操作题得分\t\t总分结果\n"
);
for(i=0
;i<n;i++){
if(s[i].sum >= 60
){
fprintf(fp,"%ld\t\t%s\t\t%.2lf\t\t%.2lf\t\t%.2lf\t\t%s\n"
,s[i].id,s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].result);
}

}

fclose
(fp);
}

// 对考生信息进行处理:计算每位考生考试总分、结果;统计考试通过的人数
int process(STU st[], int n, STU st_pass[])
{
int i,j,cnt = 0
;
float
zongfen;
for(i = 0
;i < n;i++){
zongfen = st[i].objective + st[i].subjective;
st[i].sum = zongfen;
if(st[i].sum >= 60.00
){
strcpy(st[i].result,"通过"
);
st_pass[cnt++] = st[i];
}
else
{
strcpy(st[i].result,"不通过"
);
}

3708039-20251230230649077-786932750

3708039-20251230230413975-1094002378

 

 


}
return
cnt;
}

实验任务6:

#include <stdio.h>
#include<stdlib.h>
#include<time.h>
#include<string.h>
#define N 100
#define M 5
int main(){
char s[N][N];
char st[N][N];
char h[N][N];
char name[N];
long long count[M],t;
int has_hit[N] = {0};
FILE *fp,*fout;
int i = 0,j,n,cnt = 0;

fp = fopen("D:\\2\\实验7数据文件及部分代码_gbk\\list.txt","r");
if(!fp) {
perror("list.txt");
return 1;
}
while(fgets(s[i], N, fp) !=NULL){
++i;
}
n = i;

srand(time(0));
for(i = 0;i < M;++i){
count[cnt] = rand()%n;
if(has_hit[count[cnt]])
continue;
has_hit[count[cnt]]= 1;
cnt++;
}

for(i = 0;i < M-1;i++){
for(j = 0;j < M-1-i;j++){
if(count[j] > count[j+1]){
t = count[j];
count[j] = count[j+1];
count[j+1] = t;
}
}
}

for(i = 0; i< M;++i){
strcpy(st[i],s[count[i]]);
printf("%s",st[i]);
}
printf("Enter name:");
gets(name);
fout=fopen(name,"w");
if(!fout){
perror(name);
return 1;
}

for(i=0;i<M;i++)
fprintf(fout,"%s",st[i]);

fclose(fp);
fclose(fout);
return 0;
}3707968-20251230205104047-1331992183

3707968-20251230205113306-709425166

 

posted @ 2025-12-31 11:29  呼-  阅读(4)  评论(1)    收藏  举报