@Resource注入

1、根据名称注入

    @Resource(name = "userService")
    private UserService userService;
@Service("userService")
public class UserServiceImpl implements UserService

2、不指定名称,根据属性名进行注入

    @Resource
    private UserService userService;
@Service("userService")
public class UserServiceImpl implements UserService

 3、根据类型进行注入

    @Resource
    private UserService userService;
@Service
public class UserServiceImpl implements UserService

 

posted @ 2023-02-26 19:49  诸葛卧龙仙人  阅读(63)  评论(0)    收藏  举报